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2 years ago

Find the slope of a line with ordered pairs (1,5) and (5,8)

Mathematics

1 answer:

klemol [59]2 years ago

6 0

Step-by-step explanation:

(1,5) (5,8)

x,y. x,y

Formula: y2-y1

x2-x1

so...

8-5= 3

5-1 = 4

so... 3

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Fittoniya [83]

Answer:

Step-by-step explanation:

200*0.30=60

Multiply the percent's by the total cost.

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2 years ago

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Find the first term and the common ratio third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

So, Common Ratio r = 2

Finding First term using eq(1)

$a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}$

So, First term a₁ = 3/2 and common ratio r = 2

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2 years ago

Solve for b: 16b = 12

Zina [86]

Answer:

b = 3/4

Step-by-step explanation:

Hi!!!

You want the value of B. To get that, we have to divide both sides by 16:

$\frac{16}{16}b =\frac{12}{16}$

$\frac{12}{16} = \frac{3}{4}$

Thus the answer to your question is $$\boxed{b = \frac{3}{4} }$ .

Check:

3/4 * 16 = 3 * 4 = 12.

12 = 12

So we are correct!!!

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2 years ago

What percent of 53 is 7

spayn [35]

7 ÷ 53
0.132075 
0.132075 * 100
13.21%

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3 years ago

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Factorise: 4x squared - 9y squared

kicyunya [14]

Here is your great answer Simplifying
4x2y + 12xy2 + 9y3

Reorder the terms:
12xy2 + 4x2y + 9y3

Factor out the Greatest Common Factor (GCF), 'y'.
y(12xy + 4x2 + 9y2)

Factor a trinomial.
y((2x + 3y)(2x + 3y))

Final result:
y(2x + 3y)(2x + 3y)

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2 years ago