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Bond [772]
3 years ago
12

Two bricklayers San and Joe are working on your house San can complete the work in 5 hours Joe can complete the work in 3 hours

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0
Guessing this is a combined work problem??? You forgot to post the question. I can solve for the time it takes them to complete the house together..

1/3 + 1/5 = 1/t
5/15 + 3/15 = 1/t
8/15 = 1/t
15/8 = t
1.875 hrs
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algol [13]
For the first store, let's calculate what he paid. Since he saved 75% and saved $15, we can calculate his expense as being
\frac{15}{0.75} - 15= 5
So $5 in the first store.

For the next store we can calculate his expense by the rewriting 85% as 0.85 and calculate it as so
\frac{17}{0.85} = 20
So $20 in the second store. Finally we can add the two together
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6 0
3 years ago
If 5 is decreased by 3 times a number the result is -4
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3 years ago
Solve the equation 9x +6=3 what is x
allochka39001 [22]

<span>9x+6=3       /-6</span>

<span /><span>9x=-3 \\  \\ x=- \frac{3}{9} ^{/3}=- \frac{1}{3}<u /></span><u />

8 0
3 years ago
Read 2 more answers
The question is shown below ↓
masya89 [10]

Answer:

Step-by-step explanation:2+2=4

6 0
3 years ago
A gardener is planting two types of trees. Type A is three feet and grows at a rate of 15 inches per year. Type B is four feet t
4vir4ik [10]

Answer:

2.4 years

Step-by-step explanation:

We can write two equations for each Type and equate and solve for unknown variable.

First, we need to make the initial height (in ft) to inches.

<u>Type A:</u>

3 feet = 3 * 12 = 36 inches

<u>Type B:</u>

4 feet = 4 * 12 = 48 inches

Let "t" be the number of years

For Type A, the equation would be:

36 + 15t  [36 inches already and 15 inches per year]

For Type B, the equation would be:

48 + 10t  [48 inches and 10 inches per year]

Now we equate and solve for "t", the time when both are same height:

36 + 15t = 48 + 10t\\15t-10t=48-36\\5t=12\\t=\frac{12}{5}\\t=2.4

Hence, after 2.4 years, both trees' heights would be same

7 0
4 years ago
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