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andriy [413]
3 years ago
14

A sexologist teaching at a university offers students the option of writing a term paper or participating in a sexuality survey.

What challenge would this pose for findings from the survey?
Biology
2 answers:
gogolik [260]3 years ago
7 0

Answer: Volunteer bias

Explanation:

In the given situation the chances of participation of males in the study of sexuality is likely to more than the females or may be male volunteer may be available more readily. As the females are more inexpressive or may feel shy when asked for their own opinion related to topic of sexuality.

But males may be more comfortable while discussing topic related to sexuality . Thus this will create volunteer bias in the subjects of study.

Amanda [17]3 years ago
6 0

Answer:

Volunteer bias.

Explanation:

The sexologist may be defined as the individuals that are expertise in the field of topic and concepts related to the study of the sex. Sexology includes the scientific study of the human sexuality.

Volunteer bias may be defined as the individuals that willingly participate in the research method. This volunteering might affect the the thinking and can develop the different approach towards the life. This research sometime can also bring inaccurate conclusion.  

Thus, the answer is volunteer bias.

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In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. What is the
Illusion [34]

In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. The frequency of individuals that are heterozygous for this allele is 0.32.

<h3>Hardy Weinberg Equilibrium Principle </h3>
  • A stable, idealized population's constant frequency of alleles and genotypes is described by the Hardy-Weinberg equilibrium principle.
  • In a sizable population, random mating, or spontaneous mutations are necessary for Hardy-Weinberg equilibrium.

The Hardy-Weinberg equation dictates that the sum of the allele frequencies for each allele at the locus must equal 1, therefore p + q = 1. The Hardy-Weinberg equation is also written as p2 + 2pq + q2 = 1, where p is the population's frequency of the "A" allele and q is that of the "a" allele.

The homozygous genotype AA frequency is represented by p2, the homozygous genotype aa frequency by q2, and the heterozygous genotype aa frequency by 2pq in the equation.

Here, q = 0.2. Because of this, p = '1- q = 1 - 0.2 = 0.8.

The population of individuals who are heterozygous will now be 2pq, or 2 * 0.8 * 0.2 = 0.32.

Hence, This indicates that the population is heterozygous with a frequency of 0.32.

To learn more about Hardy Weinberg Principle refer to:

brainly.com/question/1365714

#SPJ4

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2 years ago
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