Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
The length is 24 because 768 is the are and to find area you would do length x width but in this case the width has already been told so you have:
32 X____=768
so you do 768÷32= 24 so that's your answer sorry for such a long explanation which probably wasn't necessary but oh well!
Answer:
y=(x+13)/3
Step-by-step explanation:
the question is not quite clear, i think u mean y= -3x + 4
then, the slope of the line perpendicular to the given line is m1.m2= -1, hence, -3.m2= -1 m2 = 1/3
y-5=1/3(x-2) y=x/3+13/3 or y=(x+13)/3
Answer:
Step-by-step explanation:
<u>Given equation</u>
<u>Answer choices</u>
A. The equation represents a proportional relationship.
- TRUE, it is in the form of y = kx
B. The unit rate of change of y with respect to x is 8.5
- TRUE, y = mx + b, the slope m = 8.5 is the rate of change
C. The slope of the line is 2/17
D. A change of 17 units in x results in a change of 2 units in y.
- False, a change of x = 17 results in 17*8.5 = 144.5 units in y
E. A change of 4 units in x results in a change of 34 units in y.
Answer:
1
Step-by-step explanation:
