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3 years ago

How to get out of an annoying class on zoom (I only did math because I’m pretty sure it’s the most popular)

Mathematics

1 answer:

posledela3 years ago

7 0

Ummm just don’t go ? To the class

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Someone help me please

Bond [772]

Answer:

Step-by-step explanation:

Plug in the standard deviation formula. This is new to me but it took some research.. Hope it helps

6 0

3 years ago

To prove :One plus cot square theta into tan theta by sec square theta = cot theta

pickupchik [31]

we are given

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$

We will simplify left side and make it equal to right side

Left side:

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we can use trigonometric identity

$1+cot^2(\theta)=csc^2(\theta)$

we can replace it

$\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

$\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}$

now, we know that

tan =sin/cos

$\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}$

we can simplify it

and we get

$\frac{cos(\theta)}{sin(\theta)}$

we can also write it as

$=cot(\theta)$

Right Side:

$cot(\theta)$

we can see that

left side = right side

so,

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$ ......Answer

6 0

3 years ago

What is |x|/-6=12 a no solution b -2or 2 c -72or72 d 72. im really confused

Kobotan [32]

Remember
|x|≥0 for every real value of x

so

|x|/-6=12
divide both sideds by -6
|x|=-2
false, the absolut value cannot be negatve

6 0

3 years ago

F(x)=x^2-5. a) f(x)=4

inysia [295]

Substitute in x to get:
4^2 = 16
16 - 5 = 9

3 0

3 years ago

Help fake answers will be reported

ankoles [38]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers