System of equation 4a +9b =8 8A +6c=-1 6b+6c=-1

1 answer:

8 0

4a + 9b + 0c = 8 ⇒ 4a + 9b + 0c = 8
8a + 0b + 6c = -1 ⇒ 8a + 0b + 6c = -1
0a + 6b + 6c = -1 12a + 9b + 6c = 7
 12a + 9b + 6c = 7 ⇒ 24a + 18b + 12c = 14
4a + 9b + 0c = 8 8a + 6b + 12c = 0 ⇒ 24a + 18b + 36c = 0
8a + 0b + 6c = -1 ⇒ 8a + 0b + 6c = -1 -24c = 14
0a + 6b + 6c = -1 ⇒ 0a + 6b + 6c = -1 -24 -24
 8a + 6b + 12c = 0 c = ⁷/₁₂
 6b + 6(⁷/₁₂) = -1
 6b + 3¹/₂ = -1
 - 3¹/₂ - 3¹/₂
 6b = -4¹/₂
 6 6
 b = ³/₄
 4a + 9(³/₄) = 8
 4a + 6³/₄ = 8
 - 6³/₄ - 6³/₄
 4a = 1¹/₄
 4 4
 a = ⁵/₁₆
 (a, b, c) = (⁵/₁₆, ³/₄, ⁷/₁₂)

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Hello help me please

Crank

Answer:

y = 1

x = -3

Step-by-step explanation:

9x + 2y = 3

-x - y = -12 (multiply second equation with 9)

9x + 2y = 3

-9x - 9y = - 108 (add these to up)

-7y = -105

y = 15 use this to find x

9x + 2y ➡ 9x + 30 = 3 ➡ 9x = -27 ➡ x = -3

6 0

3 years ago

Consider the series 4 + 12 + 36 ... Find the sum of the first 9 terms.

jeyben [28]

Answer:

39364

Step-by-step explanation:

You can simplify the equation to make 4(1+3+9...) The nth term is therefore $3^{n-1}$ so u can substitute that into the equation so 4( $3^{n-1}+ 3^{n} + 3^{n+1}$ ..). This would simplify to 4( $3^0 +3+3^2$ + $3^3+3^4+3^5+3^6+3^7+3^8$ ). By simplifying this, you can make it so 4( $2^2+6^2+18^2+42^2+81^2$ ) = 4(4+36+324+2916+6561) =39364