2 years ago

Algebra 1. Please show work.

1 answer:

7 0

Try this:
Given:
$\left \{ {{x-y=1} \ [1] \atop {x+y=3} \ [2]} \right.$
1) [1]+[2]: 2x=2 ⇒ x=2
2) [2]-[1]: 2y=1 ⇒ y=1.
3) answer: (2;1)

You might be interested in

Please help. Thx!

makvit [3.9K]

Answer:

use G

authmaths

Step-by-step explanation:

4 0

1 year ago

Round 18.194 to the place named tenth hundred ones

Novay_Z [31]

tenth place: 18.2

hundredth place: 18.19

one place: 18

tens place: 20

hundred place: 0

I didn't know which one you needed so I did a bunch

6 0

2 years ago

List the correlation coefficients in order from least to greatest: 0.79,-0.43,-0.4,0.82,0.08

Mars2501 [29]

-0.43,-0.4,0.08,0.79,0.82

6 0

2 years ago

Read 2 more answers

Find Aut( 15). Use the Fundamental Theorem of Abelian Groups to express this group as an external direct product of cyclic group

Eduardwww [97]

Answer:

The solution is attached in the picture below

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to fi

Keith_Richards [23]

Answer:

P(X = 12) = 0.0064.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 30, p = 0.2$

We want P(X = 12). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{30,12}.(0.2)^{12}.(0.8)^{18} = 0.0064$

P(X = 12) = 0.0064.

6 0

2 years ago