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UkoKoshka [18]
3 years ago
10

Maya is going to an amusement park. The price of admission into the park is $10, and once she is inside the park she will have t

o pay two dollars for every ride she rides on. How much money would Maya have in total if she goes on 15 right? How much would she have to pay if she goes on r rides
Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

15 rides= 40 and r rides= 10+2r

Step-by-step explanation:

weqwewe [10]3 years ago
4 0

Answer:

it 40

Step-by-step explanation:

10+5(15times 2)

10+30=

40 it should be it

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Answer:

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Step-by-step explanation:

first distribute the 9 to the (x-y) and you get

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Okay!

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Hannah and Zach together earn $950 for an
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Answer:

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Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=
jasenka [17]

Answer:

The function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

The function is continuous at point x=36 if:

  1. The function \\ f(x) exists at x=36.
  2. The limit on both sides of 36 exists.
  3. The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}

\\ f(36) = \frac{36*6}{900} = \frac{6}{25}

The limit of the \\ f(x) is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Since

\\ f(36) = \frac{6}{25}

And

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Then, the function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

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