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4 years ago

11

(x^5+15x^4+54x^3-25x^2-75x-42)/(x+8)

1 answer:

BaLLatris [955]4 years ago

5 0

Do you want it graph or do you want it solved

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HELPPS PLEASE FOR BRIANILIST

const2013 [10]

if 2 pencils costs $1.60, then divide that by two and youll see that one pencil is 0.80¢. so that means 0.80 x 5 equals 4

That explains why 5 pencils are $4

And so on.

Answer: 0.80¢

6 0

3 years ago

Read 2 more answers

I need help...........

bogdanovich [222]

Hello,

The answer is C, refer to this picture for an explanation.
Have a great day!!
Brainliest??

4 0

3 years ago

Which is NOT an example of continuous data?

kicyunya [14]

Answer:

The answer is D.

Step-by-step explanation:

Continuous data examples include weight, temperature, height, length and time. It eliminates the first three options leaving D as the answer, which is NOT an example of continuous data.

I do hope this helps :DD

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3 years ago

Read 2 more answers

Solve for x if log 9 base x + log 3 base x^2 = 2.5

Y_Kistochka [10]

Not sure if the equation is

$\log_9x+\log_3(x^2)=\dfrac52$

or

$\log_x9+\log_{x^2}3=\dfrac52$

If it's the first one:

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot9^{\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot(3^2)^{\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{2\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^2)^2}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^4)}$

$9^{\log_9x+\log_3(x^2)}=x\cdot x^4$

$9^{\log_9x+\log_3(x^2)}=x^5$

On the other side of the equation, we'd get

$9^{5/2}=(3^2)^{5/2}=3^{2\cdot(5/2)}=3^5$

Then

$x^5=3^5\implies\boxed{x=3}$

If it's the second one instead, you can use the same strategy as above:

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot x^{\log_{x^2}3}$

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot\left((x^2)^{1/2}\right)^{\log_{x^2}3}$

(Note that this step assume $x>0$ )

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{(1/2)\log_{x^2}3}$

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{\log_{x^2}\sqrt3}$

$x^{\log_x9+\log_{x^2}3}=9\sqrt3$

Then we get

$9\sqrt3=x^{5/2}\implies x=(9\sqrt3)^{2/5}\implies\boxed{x=3}$

6 0

3 years ago

Find the value of x for the given value of y. y=9−7x; y=37

MrMuchimi

Answer:

For y=37, x= -4

Step-by-step explanation:

We have to find the value of x, when y=37 is the given value for the given equation

$y=9-7x$

Putting the value of y=37 in the equation to find the 'x'

$y=9-7x$

$37=9-7x\\7x=9-37\\7x=-28\\x=-4$

So, for the value of y=37, the value of $x=-4$

6 0

3 years ago