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dedylja [7]
2 years ago
10

1.) How do parks and other green spaces benefit a community?

Computers and Technology
1 answer:
vagabundo [1.1K]2 years ago
8 0
#1 is A and #2 is B, but I don't know about #3 and #4.
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______ is the ability of a system to do more than one thing at a time. A. Multibusing c. online processing b. Multiprocessing d.
mrs_skeptik [129]

Answer:

Multiprocessing.

Explanation:

In multiprocessing the system uses two or more processors to do more tasks simultaneously.

8 0
2 years ago
​______________________ is a general security term that includes computer​ viruses, worms, and trojan horses.
VashaNatasha [74]
Malware
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3 years ago
A struck-by hazard can be described as anytime a worker ___________.
solong [7]
A...........................................
7 0
2 years ago
Read 2 more answers
A. Write a program that asks the user to enter an integer, then prints a list of all positive integers that divide that number e
kobusy [5.1K]

Answer:

Following are the program in python language the name of the program is factors.py

num= int(input("Please enter a positive integer: "))#Read the number by user

print("The factors of ",num,"are:")

for k in range(2,num): #iterating over the loop

   if(num%k==0): #checking the condition

       print(k)#display the factor

Output:

Please enter a positive integer: 12

The factors of 12 are:

2

3

4

6      

Explanation:

Following are the description of the program

  • Read the number by user in the "num" variable
  • Iterating the for loop from k=2 to less then "num".
  • In the for loop checking the factor of "num"  variable by using % operator.
  • Finally display the factor by using print function
4 0
3 years ago
Can someone please help me in answering this!?! <br> The language is C++
Llana [10]

Here is a somewhat cryptic solution that works:

#include <algorithm>

#include <cstdlib>

using namespace std;

void q(char c, int count)

{

for (int i = 0; i < count; i++) {

 putchar(c);

}

}

void p(int b1, int plusses)

{

q(' ', b1);

q('+', plusses);

}

int main()

{

for (int i = -3; i <= 3; i++)

{

 int pl = min(6, (3 - abs(i)) * 2 + 1);

 p(6-pl, pl);

 i == 0 ? p(0, 6) : p(6, 0);

 p(0, pl);

 putchar('\n');

}

getchar();

}


5 0
3 years ago
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