Answer:
It uses simple words and symbols to communicate the design of a program
Explanation:
A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer on how to perform a specific task and solve a particular problem.
A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications. There are seven (7) main stages in the creation of a software and these are;
1. Planning.
2. Analysis.
3. Design.
4. Development (coding).
5. Testing.
6. Implementation and execution.
7. Maintenance.
A pseudocode refers to the description of the steps contained in an algorithm using a plain or natural language. Also, a pseudocode gives a summary of the steps adopted during a software development process using simple (concise) words and symbols.
This ultimately implies that, a pseudocode uses simple words and symbols to communicate the design of a program.
Answer:
Mouse and Keyboard are the devices which can be used to give input to the computer.
Explanation:
Mouse and Keyboard both are connected with the CPU via USB cable. Mouse consists of 3 major buttons, left button(for click to get the task to be done), right button (to get options) and wheel (to scroll up and down the page on screen). Keyboard is use to type text and letters as per need.
Answer:
True
Explanation:
The while loop is going to be executed until the condition is false.
Since <em>k</em> is initially equal to 1, the loop will execute 88 times. One asterisk will be printed and <em>k</em> will be incremented by one during each iteration.
When <em>k</em> becomes 89, the condition will be false (89 is not smaller or equal to 88) and the loop will stop.
Answer:
(a) someFunc(3) will be called 4 times.
(b) For non negative number n someFunc method calculates 2^2^n.
Explanation:
When you call someFunc(5) it will call someFunc(4) two time.
So now we have two someFunc(4) now each someFunc(4) will call someFunc(3) two times.Hence the call to someFun(3) is 4 times.
someFunc(n) calculates someFunc(n-1) two times and calculates it's product.
someFunc(n) = someFunc(n-1)^2..........(1)
someFunc(n-1)=someFunc(n-2)^2..........(2)
substituting the value form eq2 to eq 1.
someFunc(n)=someFunc(n-2)^2^2
.
.
.
.
= someFunc(n-n)^2^n.
=2^2^n
2 raised to the power 2 raised to the power n.
Answer:
I don't know the exact fix to this because I don't know exactly what you're talking about, but I do suggest you instead just highlight with shift and the arrow keys to make it much simpler.
