1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natita [175]
3 years ago
8

HAve a good week lads, good luck on work :D

Computers and Technology
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

v; its alright.

Explanation: none v;

Andrej [43]3 years ago
8 0

Answer:

life is ok ig

Explanation:

i need sum one to talk to

You might be interested in
What careers are most likely to require business skills
olchik [2.2K]

i would say maybe an accountant, entrepreneur, business reporter, or something like that.

8 0
3 years ago
A fireplace in a blacksmith shop is called a
astraxan [27]
They are called forges
5 0
3 years ago
Which format is used for audio files?
Arisa [49]
Audio format is used for audio files
7 0
3 years ago
Read 2 more answers
What would be some reasons to change the default page<br> encoding?
madam [21]

Answer:

Synchronization with the document for one reason or another

5 0
3 years ago
Produce an infinite collection of sets A1,A2,A3, . . . with the property that every Ai has an infinite number of elements, Ai ∩
atroni [7]

Answer:

Produce an infinite collection of sets A1,A2,A3, . . . with the property that every Ai has an infinite number of elements, Ai ∩ Aj = ∅ for all i = j, and [infinity] i=1 Ai = N.

Explanation:

Solution

For n ∈ N,

define  A_n = {2 ^n−1  ,(3)(2n−1 ),(5)(2^n−1 ),(7)(2^n−1 ), . . .}

I.e. A_n is all odd multiples of 2^n−1 . We must show that these sets satisfy the desired properties.

• (Infinite Number of Elements).

It is clear that the set A_n = {2 ^n−1 ,(3)(2^n−1 )(5)(2^n−1 ),(7)(2^n−1 ), . . .}  has infinitely many elements.

• (Disjoint).

Given A_n and A_m with n ≠ m, we can assume, without loss of generality, that n < m. Suppose  that there existed some x ∈ A_n ∩ A_m. Then by definition of these sets, there exists some odd numbers k  and l such that x = 2^n−1 . k = 2^m−1  . l.

However since n < m, we have that n ≤ m − 1, and therefore we  can write 2^m−1 = (2^n )(2 i ) with i ≥ 0. Hence we have 2^n−1 . k = 2^n. 2 ^i. l  

Dividing both sides by 2^n−1 yields  k = (2)(2^i ) .l, which contradicts the assumption that k is odd. Therefore A_n ∩ A_m = ∅.

• (Union is N).

We want to show that  [infinity] i=1 A_n = N.

(⊆). Since each A_n is a subset of N, the union of these sets is a subset of N as well.

(⊇).Given any x ∈ N, we can write x = 2^n−1 . k for some n ∈ N where k is odd. Then x ∈ A_n, as  desired.

5 0
3 years ago
Other questions:
  • Consider a multiprocessor CPU scheduling policy. There are 2 options: 1) a singlecommon ready queue of jobs; when a CPU becomes
    8·1 answer
  • An analyst is reviewing the logs from the network and notices that there have been multiple attempts from the open wireless netw
    13·1 answer
  • Banking Account
    9·1 answer
  • Who is the three president of somalia​
    8·2 answers
  • Which organization plays a key role in development of global health informatics?
    9·1 answer
  • Roark has just joined a company and in his role as a lead analyst, he will be responsible for determining which systems developm
    11·1 answer
  • If cell G7 contains the function ________, it states that if the value in cell C3 is 9, the number 7 will be assigned to cell G7
    6·1 answer
  • What is Japanese tradition?
    8·2 answers
  • Will this website ever get itself together to stop people from sending links?
    9·1 answer
  • Another name of computer program is
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!