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3 years ago

Which letter has at least one line of symmetry? R Q T P

Mathematics

1 answer:

irga5000 [103]3 years ago

5 0

T has at least one line of symmetry because if you cut it out, you can fold it in half evenly

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1. Find the mean for 2, 5, 9, 4

Reil [10]

Answer:

Answer 1. 5 Answer 2. 60 Answer 3. 37

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

3 years ago

PLEASEEE I NEED HELPPP!!!!

taurus [48]

Answer:

#carry on learning

mark me as brainliest

Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)

I really need this question answered

By:

I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).

I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.

The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:

y = 6x + b

We need to find b, so substitute the point (-5,4) that we know is on the line:

4 = 6*(-5) + b and solve for b

4 = -30 + b

b = 34

The line is y = 6x + 34

4 0

2 years ago

IF the sum of four times a number and four less than three times a number is seventeen what is the number

Virty [35]

Answer: 3

Step-by-step explanation: This equation can be written as 4x+3x-4=17

We can now solve.

Moving the 4 to the other side (adding) and we get 21.

Now we have 4x+3x. Adding like terms, we get 7x = 21. Now we divide by 7.

X = 3.

3 0

2 years ago

Please help!! 10 extra points

Igoryamba

$HEY THERE !!$

As we know that cotx= 1/tanx

cot36° = 1/tan36°

=>cot36°= 1/0.726543

=>so cot 36°= 1.376382

So correct answer is option D.

HOPR YOU LIKED.

7 0

3 years ago