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3 years ago

Which letter has at least one line of symmetry? R Q T P

Mathematics

1 answer:

irga5000 [103]3 years ago

5 0

T has at least one line of symmetry because if you cut it out, you can fold it in half evenly

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I marked all 3 parts. I need to know part C (the shaded part). anybody mind helping?

Mnenie [13.5K]

Answer:

Area of shaded part ABCEF = 66 sq.cm

Step-by-step explanation:

AB = 8cm

CD = 8cm

Let DE = x cm

CE = 3x cm

CD = CE + DE = 8cm

x + 3x = 8

4x = 8

x = 8/4 = 2 cm

DE = 2cm

CE = 3 * 2 = 6 cm

Area of triangle ADE = 1/2 * base * height

= 1/2 * DE * AD

= 1/2 * 2 * 11 = 11 sq. cm

Area of triangle AEF = Area of triangle ADE = 11 sq. cm

Area of Rectangle ABCD = l * b = 8 * 11 = 88 sq.cm

Area of shaded part ABCEF = Area of Rectangle ABCD - (Area of triangle AEF + Area of triangle ADE)

= 88 - ( 11 + 11 ) = 88 -22 = 66 sq.cm

6 0

3 years ago

What is the value of x in the equation log5 x = 4 jmap?

steposvetlana [31]

To solve for x we proceed as follows:
from the laws of logarithm, given that:
log_a b=c
then
a^c=b
applying the rationale to our question we shall have:
log_5 x=4
hence
5^4=x
x=625
Answer: x=625

5 0

4 years ago

A toy maker claims his best product has an average lifespan of exactly 14 years. A skeptical quality control specialist asks for

slamgirl [31]

Answer:

interval = [17.3948 , 20.6052]

Step-by-step explanation:

given,

random sample (n) = 45

average product lifespan = 19 years

standard deviation = 4 years

confidence interval of 99 % = ?

we know,

t* = qt(1.99/2 + 44 ) = qt(0.995,44)

t* = 2.692

so,

interval

$x = 19 \pm t* \times (\dfrac{s}{\sqrt{n}})$

$x = 19 \pm 2.692 \times (\dfrac{4}{\sqrt{45}})$

$x = 19 \pm 2.692 \times 0.5963$

$x = 19 \pm 1.6052$

interval = [19 - 1.6052 , 19 + 1.6052]

interval = [17.3948 , 20.6052]

4 0

3 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

3 years ago

Question in photo! giving away master

aniked [119]

Answer:

D.) -3

Step-by-step explanation:

N is greater than -4 and less than -2.

Therefore, -3 is N since it is between -4 and -2.

6 0

3 years ago