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3 years ago

Which letter has at least one line of symmetry? R Q T P

Mathematics

1 answer:

irga5000 [103]3 years ago

5 0

T has at least one line of symmetry because if you cut it out, you can fold it in half evenly

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It takes 6 and 1/2 cups of chocolate syrup to make 4 and 1/2 gallons of milk. How many cups of syrup would it take to make 9 gal

Eva8 [605]

Answer:

6.5 /4.5

x/9

x=13 cups

hope this helps you

4 0

3 years ago

URGENT: (TIMED) Determine the equation of the circle graphed below.

Shtirlitz [24]

Answer:

$(x-3)^2 + (y-2)^2 = 16$

Step-by-step explanation:

This is because the centre is at (3,2) and the radius of the circle is 4 and you square all the terms to find the equation of the circle.

5 0

2 years ago

Find, correct to the nearest degree, the three angles of the triangle with the given vertices. A(1, 0, âˆ’1), B(4, âˆ’3, 0), C(1

zavuch27 [327]

Answer:

Angle at vertex A : 59.2° B: 61.7° C : 59.1°

Step-by-step explanation:

1. First find the length of the vectors

AB = B-A = (4-1, 3-0, 0-1) = (3, 3, -1)

AC = C-A = (1-1, 4-0, 3-1) = (0, 4, 2)

BC = C-B = (1-4, 4-3, 3-0) = (-3, 1, 3)

2. Find magnitude of the vectors

|AB| = √(3^2+3^2+〖(-1)〗^2 )=√19

|AC| = √(0^2+4^2+2^2 )=2√5

|BC| = √(〖(-3)〗^2+1^2+3^2 )=√19

3. Find the angles between them

cos θ = (a.b)/(|a||b|) -----> θ = arc cos ((a.b)/(|a||b|))

AB, AC : θ =arc cos (AB.AC)/(|AB||AC|) = arc cos ( (3.0+3.4+ -1.2)/(√19 x 2√5)= 10/(2√95) ) =59.136, which is approximately 59.14°

AB, BC : θ =arc cos (AB.BC)/(|AB||BC|) = arc cos( (3.-3+3.1+ -1.3)/(√19 x √19)= (-9)/19 ) = 118.27°

Because of the direction of BC is pointing relative to AB this is the angle outside the triangle, and we should find the supplementary angle.

180-118.27 = 61.73°

If we used –(BC) = CB in the formula (just negate the numerator) we would have gotten the correct angle on first try.

The 3rd angle should be what’s left after subtracting from 180°;

180-61.73-59.14 = 59.13 °

You can confirm using the formula again :

AC, BC : θ =arc cos (AC.BC)/(|AC||BC|) = arc cos( (0.-3+4.1+ 2.3)/(√19 x 2√5)= 10/(2√95) = 59.13°

Rounding everything up so they add up to 180 degrees we have Angle at vertex A : 59.2° B: 61.7° C : 59.1°

7 0

3 years ago

A GMC dealer believes that demand for 2005 Envoys will be normally distributed with a mean of 200 and standard deviation of 30.

irina1246 [14]

Answer:

The correct answer to the following question will be "280 units".

Step-by-step explanation:

The given values are:

Mean = 200

Standard deviation = 30

Let's ask that the supplier needs to reach 99.9% of the standard of operation. To reach this quality of operation, she has to preserve an inventory of

Now,

⇒ $Mean + 3\times sigma$

On putting the values, we get

⇒ $200+3\times 30$

⇒ $200+90$

⇒ $290 \ units$

290 units would then accomplish a level of service of 99.9%.

Half unpurchased units can indeed be purchased at $30000 i.e. no failure. If he requests 300, there will be losses on 5 products that are unsold.

Hence, ordering 280 units seems to be preferable

3 0

3 years ago

The function f(t) = 5 cos(pi over 6t) + 7 represents the tide in Stanley Sea. It has a maximum of 12 feet when time (t) is 0 and

Juliette [100K]

The function for the height is
$f(t) = 5cos( \frac{ \pi }{6} t)+7$

f(0) = 5 cos(0) + 7 = 5 + 7 = 12 (verified)
The period is T = 12 hours.

After 4 hours (t = 4), the height is
$f(4) = 5cos( \frac{ 4\pi }{6} )+7 = 5*(-0.5)+7=4.5$

A graph of f(t) confirms the answer.

Answer: 4.5 ft

4 0

3 years ago

Read 2 more answers