Answer:
14
Step-by-step explanation: 2(4x+6)=
\,\,34-3x
34−3x
Since HJ is a midsegment, twice HJ is equal to EG.
8x+12=
8x+12=
\,\,34-3x
34−3x
Distribute.
8x+12=
8x+12=
\,\,-3x+34
−3x+34
Communicative property to change the order
\color{red}{+3x}\phantom{+12}\phantom{=}
+3x+12=
\,\,\color{red}{+3x}\phantom{+34}
+3x+34
+3x to both sides.
11x+12=
11x+12=
\,\,34
34
\phantom{11x}\color{red}{-12}\phantom{=}
11x−12=
\,\,\color{red}{-12}
−12
-12 to both sides.
11x=
11x=
\,\,22
22
\frac{11x}{11}=
11
11x
=
\,\,\frac{22}{11}
11
22
Divide both sides by 11
x=
x=
\,\,2
2
Value of x
HJ=
HJ=
\,\,4x+6
4x+6
Value of HJ
HJ=
HJ=
\,\,4(2)+6
4(2)+6
Plug in x.
HJ=
HJ=
\,\,8+6
8+6
Multiply.
HJ=
HJ=
\,\,14
14
Answer: LMNO is a rhombus
Step-by-step explanation: Since LMNO= Mo x LN, Point M=LM x ON, given these circumstances, we know that LMNO is a rhombus from the sides and angles equation.
Answer:
perimeter is 4 sqrt(29) + 4pi cm
area is 40 + 8pi cm^2
Step-by-step explanation:
We have a semicircle and a triangle
First the semicircle with diameter 8
A = 1/2 pi r^2 for a semicircle
r = d/2 = 8/2 =4
A = 1/2 pi ( 4)^2
=1/2 pi *16
= 8pi
Now the triangle with base 8 and height 10
A = 1/2 bh
=1/2 8*10
= 40
Add the areas together
A = 40 + 8pi cm^2
Now the perimeter
We have 1/2 of the circumference
1/2 C =1/2 pi *d
= 1/2 pi 8
= 4pi
Now we need to find the length of the hypotenuse of the right triangles
using the pythagorean theorem
a^2+b^2 = c^2
The base is 4 ( 1/2 of the diameter) and the height is 10
4^2 + 10 ^2 = c^2
16 + 100 = c^2
116 = c^2
sqrt(116) = c
2 sqrt(29) = c
Each hypotenuse is the same so we have
hypotenuse + hypotenuse + 1/2 circumference
2 sqrt(29) + 2 sqrt(29) + 4 pi
4 sqrt(29) + 4pi cm
Xy = 6
x = 2
2y = 6
y = 6÷2
y = 3
x + y = (2) + (3) = 5
