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3 years ago

Pls help jwjwkwkwwkwkwkwkwkkwwkkwkwwkkwkw

Mathematics

1 answer:

lara31 [8.8K]3 years ago

6 0

Answer:

o,-3 and 1.5,0

Step-by-step explanation:

You can find a calculator on a website called Desmos that might help answer related questions.

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URGENT! 100 POINTS TO SOLVE!

masya89 [10]

Answer:

20/5 = x /4 x = 80/5 = 16

x - 10 / 39 = 5/15 = 1/3

3x - 30 = 39

3x = 69

x = 23

(2x + 10 ) * 4 = 10 *(x + 3)

8x + 40 = 10x + 30

2x = 10

x = 4.

AE = 2(5) + 10 = 20, hope this helped.

3 0

2 years ago

Read 2 more answers

1. Thales, an ancient Greek mathematician, and philosopher used certain triangles to find the height of unknown objects. He wait

charle [14.2K]

An equilateral triangle.

all sides are the same so the higth of the object will be the same as length of the shadow.

7 0

3 years ago

Which of the following is a polynomial A.x^2+2 B.(x^8-2)/(x^-2+3) C. 7x^7-2x^-4+3 D.x^x-1

EastWind [94]

<span> A. x²+2 - a polynomial
B.(x⁸-2)/(x⁻²+3) rational function
C. 7x⁷-2x⁻⁴+3 (It has negative value of exponent, so it cannot be a polynomial.)
D.x^x-1 (x is an exponent it cannot be a polynomial)</span>

6 0

3 years ago

ITS TIMED PLEASE HELP

Lubov Fominskaja [6]

Answer:

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

$f(x)=\frac{1}{2}x^{2}-4x+5$

Convert to vertex form

$f(x)-5=\frac{1}{2}x^{2}-4x$

Factor the leading coefficient

$f(x)-5=\frac{1}{2}(x^{2}-8x)$

$f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x-4)^{2}$

$f(x)=\frac{1}{2}(x-4)^{2}-3$

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

5 0

3 years ago

Group Tens as Hundreds

IrinaK [193]

Answer:

Write how many groups of tens there are

Circle groups where there are ten groups of tens

Write how many hundreds there are

Write the total number of tens and hundreds there are

3 0

3 years ago

Pls help jwjwkwkwwkwkwkwkwkkwwkkwkwwkkwkw​

Pls help jwjwkwkwwkwkwkwkwkkwwkkwkwwkkwkw