Why is it that when comparing a squares area with a rectangles area, with the SAME PERIMETER, that the square has a greater area
1 answer:
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Answer:
Step-by-step explanation:
So we have the system:
If we isolate the x-variable in the first equation:
Subtract 2y from both sides:
Divide both sides by -1:
Therefore, we would substitute the above into the second equation:
The answer is 2y+6
Further notes:
To solve for the system, distribute:
Simplify:
Subtract:
Divide:
Now, substitute this value back into the isolated equation: