M= (y2-y1)/ (x2-x1)
Plug the points in.
-9-6/1-1
-15/0 or -15. The slope of the line is -15.
I hope this helped you!
Brainliest answer would be greatly appreciated!
Answer:
x=109 degrees
Step-by-step explanation:
so 33+39+x=180 degrees because of sum of angles in a triangle theorem. Then now you solve because of algebra
Check the picture below.
so we can say that two sides are "4" each in length, since opposite sides are equal, let's find how long the slanted sides are.
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[3 - (-4)]^2 + [5 - 2]^2}\implies d=\sqrt{(3+4)^2+3^2} \\\\\\ d=\sqrt{49+9}\implies d=\sqrt{58} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{4~~ + ~~4~~ + ~~\sqrt{58}~~ + ~~\sqrt{58}\implies 8+2\sqrt{58}}](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-4%7D~%2C~%5Cstackrel%7By_1%7D%7B2%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B3%7D~%2C~%5Cstackrel%7By_2%7D%7B5%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B%5B3%20-%20%28-4%29%5D%5E2%20%2B%20%5B5%20-%202%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%283%2B4%29%5E2%2B3%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B49%2B9%7D%5Cimplies%20d%3D%5Csqrt%7B58%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Perimeter%7D%7D%7B4~~%20%2B%20~~4~~%20%2B%20~~%5Csqrt%7B58%7D~~%20%2B%20~~%5Csqrt%7B58%7D%5Cimplies%208%2B2%5Csqrt%7B58%7D%7D)
3x (x + 2)²
3x ( x² + 4)
3x³ +12x
~Hope I helped!~
Answer: Histogram
You can eliminate the stem and leaf plot, since it tells you the amount of values.
You can eliminate the dot plot, since it also shows you the number of values.
You can eliminate the frequency table, since it calculates the frequency of a number.
Thus, the answer is the histogram.
