Answer:
a.) April has 30 days
If you for option No.2, you would have:
[day, amount($)]
1, 0.01
2, 0.02
3, 0.04
4, 0.08
5, 0.16
6, 0.32
7, 0.64
8, 1.28
9, 2.56
10, 5.12
11, 10.24
12, 20.48
13, 40.96
14, 81.82
15. 163.48
16, 327.68
17, 655.36
18, 1310.72
19, 2621.44
20, 5242.88
21, 10,485.76
22, 20,971.52
23, 41,943.04
24, 83,886.08
25, 167,772.16
26, 335,544.32
27, 671,088.64
28, 1,342,177.28
29, 2,684,354.56
30, 5,368,709.12
Option 2 grants you more than 5 times as much as Option A and is therefore obviously better.
b.) A diagram would show first a slow rise, than a steeper and steeper rise, then would almost growvertically. exponential growth
#coronatime
The most elegant form to describe the given numbers would simply be
$=1*2^x
You start with one, eich doubles after a day (x=1). x is the number of days and how often you multiply by 2
c.) Wasn't sure without calculating, but I guessed Opt.2, because it seemed that one should be tricked into choosing Opt.1
Have a nice day
Brainliest would be appreciated
If there are questions left, feel free to ask them
Answer:
9.) 
10.) 
11.) 
minutes of calling would make the two plans equal.
12.) Company B.
Step-by-step explanation:
Let <em>t</em> equal the total cost, and <em>m,</em> minutes.
Set up your models for questions 9 & 10 like this:
<em>total cost = (cost per minute)# of minutes + monthly fee</em>
Substitute your values for #9:
Substitute your values for #10:
__
To find how many minutes of calling would result in an equal total cost, we have to set the two models we just got equal to each other.
Let's subtract 
from both sides of the equation:
Subtract 
from both sides of the equation:
Divide by the coefficient of 
, in this case: 
__
Let's substitute 
minutes into both of our original models from questions 9 & 10 to see which one the person should choose (the cheaper one).
Company A:
Multiply.
Add.
Company B:
Multiply.
Add.
<em />
It would be a 90%. In the calculator 18 is what percent of 20.
The area under the speed curve tells you how much distance the vehicle covers.
The distance for first 30 s corresponds to the area of a rectangle with height <em>k</em> m/s and length 30 s, or
(<em>k</em> m/s) (30 s) = 30<em>k</em> m
The distance for the last 20 s corresponds to the area of triangle with height <em>k</em> m/s and length 20 s, or
1/2 (<em>k</em> m/s) (20 s) = 10<em>k</em> m
If the total distance traveled was 1.7 km = 1700 m, then
30<em>k</em> + 10<em>k</em> = 1700
40<em>k</em> = 1700
<em>k</em> = 42.5
