Question

In triangle ABC, mA 55, mB-30, and a 8. Which equation should you solve to find b?

Answer 1

Answer:

C. $\frac{\text{Sin 55}^{\circ}}{8}=\frac{\text{Sin 30}^{\circ}}{b}$

Step-by-step explanation:

We have been given that in triangle ABC, mA 55, mB-30, and a 8. We are asked to find the equation that we can use to solve the length of side b.

We will use law of sines to solve our given problem.

$\frac{\text{Sin A}}{a}=\frac{\text{Sin B}}{b}=\frac{\text{Sin C}}{c}$, where A, B and C represents angle of a triangle corresponding to sides a, b and c respectively.

Upon substituting our given values in law of sines we will get,

$\frac{\text{Sin 55}^{\circ}}{8}=\frac{\text{Sin 30}^{\circ}}{b}$

Therefore, the option C is the correct choice.

Answer 2

Answer: C . sin55/8 = sin30/b