The next two term is 13 and 16 respectively.
Step-by-step explanation:
here,
a1 = -2
a2 = 1
a3 = 4
a4 = 7
a5 = 10
So, d = <u>a2 - a1</u> = 1 - (-2) = 3
= <u>a3 - a2</u> = 4 - 1 = 3
Here, <u>Common difference</u> is <u>same everywhere</u> and the value of d is 3
Then,
<em>To find 6th term of this sequence</em>
<u>a6 = a5 + d</u>
= 10 + 3
a6 = 13
<em>To find </em><em>7</em><em>t</em><em>h term of this sequence</em>
<u>a7 = a6 + d</u>
= 13 + 3
a7 = 16
Thus, The next two term is 13 and 16 respectively.
-<u>T</u><u>h</u><u>e</u><u>U</u><u>n</u><u>k</u><u>n</u><u>o</u><u>w</u><u>n</u><u>S</u><u>c</u><u>i</u><u>e</u><u>n</u><u>t</u><u>i</u><u>s</u><u>t</u>
Answer:
https://jbarrueta.weebly.com/uploads/5/3/2/9/53297595/lesson2.2.2.pdf
Step-by-step explanation:
here's a link
w+5=8 because 3+5=8 so
w+5=9 because we put w as 4
w +5=10 so w is 5
Answer:
$8511.11
Step-by-step explanation:
Each year, the amount Walter owes is multiplied by 1.06, so at the end of 6 years, Walter owes 1.06^6 times the amount he borrowed.
he will pay $6,000×1.06^6 ≈ $8511.11
_____
At the end of the first year, Walter owes the original loan amount plus 6% interest. That total is ...
$6000 + 0.06×6000 = $6000×1.06
At the end of the following year, he owes 1.06 times that amount, or ...
6000×1.06²
The amount owed is multiplied by 1.06 each year until Walter pays off the loan.
This isn’t an answer but we gotta see the question to answer it ☠️☠️