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bija089 [108]
3 years ago
7

The area of a rectangle is 70 yd^(2) and the length of the rectangle is 11 yd less than three times the width. find the dimensio

ns of the rectangle

Mathematics
2 answers:
Orlov [11]3 years ago
4 0
Pretty sure this is the answer, hope this helps :')

Vikki [24]3 years ago
3 0
◆ AREA OF 2-D FIGURES ◆

let \: the \: length \: of \: rectangle \: be \: l  \: yd\:  \\  \\ and \: width \: of \: rectangle \: be \: b  \: yd\\  \\ now \: , \: its \: given \: that \: , \\  \\ length \: of \: rectangle \: is \: 11 \: yd  \\ \: less \: than \: 3 \: times \: the \: width \: , \\  \\ l = 3b - 11 \:  \:  \:  \\  \\ area \: of \: rectangle \: = length \times width \\  \\ 70 = (3b - 11) \times b \\  \\ 3 {b}^{2}  - 11b - 70 = 0 \\  \\ 3 {b}^{2}  - 21b + 10b - 70 = 0 \\  \\ 3b(b - 7) + 10(b - 7) = 0 \\  \\ (3b + 10)(b - 7) = 0 \\  \\ solving \: , \: we \: get \: , \\ b =  \frac{ - 10}{3}  \:  \:  \:  \: or \:  \:  \: b = 7 \\  \\ side \: of \: any \: shape \: can \: not \: be \: negative \: , \\  \\ therefore \: , \\  \\ width \:  = 7 \: yd  \:  \:  \:  \:  ans.\\  \\ length \:  = 10 \: yd \:  \:  \: ans.
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