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2 years ago

Please answer this question, 30 points and will give brainliest!

Mathematics

1 answer:

kotykmax [81]2 years ago

6 0

Answer:

∠C = 80 ° ; ∠ T = 40°.

Step-by-step explanation:

Triangle CRS is isosceles because it has two sides of equal length. (CR and CS are radii).

An isosceles triangle has also two equal angles, which means that ∠CRS= ∠CSR.

Therefore, ∠C = 80 ° (180° – 50° - 50°) because the sum of angles in a triangle is 180 degrees.

∠C is the central angle of the arc RS.

∠ T is the inscribed angle of the arc RS.

An inscribed angle is half of a central angle that subtends the same arc on the circle, so the inscribed angle ∠ T is half of the central angle ∠C. Since ∠C = 80 °, we can easily determine the measure of ∠ T:

80° divided by 2 is 40°.

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What is the difference of the fractions? Use the number line to help find the answer. 7

san4es73 [151]

Answer:

C.) -7/5

Step-by-step explanation:

To subtract fractions, we need to have common denominators. So first, we will change -1 1/5 to -6/5.

Now we will change the denominator of both -6/5 and 1/2 to 10.

We now have:

5/10 and -12/10

5-12=-7

So the answer would be -7/5

If we want to use the number line, we would first find 5/10 (1/2) on the graph and count down (to simulate subtraction) 12 units since we are subtracting by 12. :))

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2 years ago

Ms Li has 4 different books and 1 red pen,1 blue pen and 1 black pen she is wrapping one book and one pen.Draw a tree diagram to

scoray [572]

12 different combinations because 4 times 3 equals 12.

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2 years ago

Ask questions slove for x 5(x-3)=15

Pavel [41]

Answer:

Step-by-step explanation:

Your answer is 6

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3 years ago

In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control

lianna [129]

Answer:

The sample space for selecting the group to test contains 2,300 elementary events.

Step-by-step explanation:

There are a total of N = 25 aluminum castings.

Of these 25 aluminum castings, n₁ = 4 castings are defective (D) and n₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

Compute the number of samples that are possible as follows:

${25\choose 3}=\frac{25!}{3!\times (25-3)!}$

$=\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300$

The sample space for selecting the group to test contains 2,300 elementary events.

6 0

3 years ago

Help what’s the answer

-BARSIC- [3]

Would be x^2-5-6 so the 0s would be (x-6)(x+1) so 6 and -1

7 0

2 years ago