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Aleksandr-060686 [28]
3 years ago
6

Please answer this question, 30 points and will give brainliest!

Mathematics
1 answer:
kotykmax [81]3 years ago
6 0

Answer:

∠C = 80 ° ; ∠ T = 40°.

Step-by-step explanation:

Triangle CRS is isosceles because it has two sides of equal length. (CR and CS are radii).

An isosceles triangle has also two equal angles, which means that ∠CRS= ∠CSR.

Therefore, ∠C = 80 ° (180° – 50° - 50°)  because the sum of angles in a triangle is 180 degrees.  

∠C is the central angle of the arc RS.

∠ T is the inscribed angle of the arc RS.

An inscribed angle is half of a central angle that subtends the same arc on the circle, so the inscribed angle ∠ T is half of the central angle ∠C. Since ∠C = 80 °, we can easily determine the measure of ∠ T:  

80° divided by 2 is 40°.

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We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

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Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

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t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

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