Answer:
a(n) = 9·6^(n-1)
Step-by-step explanation:
The general term a(n) of a geometric sequence with first term a(1) and common ratio r is given by ...
a(n) = a(1)·r^(n-1)
Your sequence has first term 9 and common ratio 54/9 = 6, so the function describing it is ...
a(n) = 9·6^(n-1)
<u>Answer:</u>
<h2>
14.21 cm</h2>
<u>Explanation:</u>
you mean the hypotenuse* lol
the hypotenuse = √(11²+9²)
the hypotenuse = √(121+81)
the hypotenuse = √(202)
the hypotenuse ≈ 14.21 cm
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term.
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression
