The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
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Answer: x-10=3
Step-by-step explanation:
The answer is b or, if it shows different its the second option x-10=3
Got it right on edge 100%
Hope I helped.
Answer:
Step-by-step explanation:
Changing Bases to Evaluate Logarithms
Apply change of base formula'
log term should be the numerator and denominator is the log base
64 is 4^3 and 16 is 4^2
Move the exponent before log
top and bottom has same log so cancel it out
1 pint equals 2 cups. 6 x 2 = 12 plus the other cup (1) is 13
Answer:
13 cups
You doubled the investment in the product. You sold it for twice what you bought it for. So it increased by $750
