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Salsk061 [2.6K]
2 years ago
12

What is the area of this figure? Enter your answer in the box.

Mathematics
2 answers:
Ivahew [28]2 years ago
6 0

Answer:

\text {Area of figure is }44 units^2

Step-by-step explanation:

Given the figure and we have to find the area of given figure.

Area of figure=ar(ABC)+ar(CDE)+ar(AEFH)+ar(GHF)

From the figure, dimensions according to square boxes can be written as

AE=HF=8 units, EF=3 units, BI=3 units, GH=2 units, AC=CE=4 units.

ar(ABC)=ar(CDE)=\frac{1}{2}\timesAC\times BI=\frac{1}{2}\times4\times3=6 units^2

ar(AEFH)=HF\times EF=8\times 3=24 units^2

ar(GHF)=\frac{1}{2}\timesHF\timesGH=\frac{1}{2}\times8\times 2=8units^2

∴ \text {Area of figure is }44 units^2

EleoNora [17]2 years ago
4 0
1/2(4) x 1 = 2

8 x 3 = 24

2( 1/2(4) x 3)= 12

2 + 24 + 12 = 38units^2
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What is the slope-intercept form of the linear equation 4x + 2y = 24? Drag and drop the appropriate number, symbol, or variable
Morgarella [4.7K]

The slope-intercept form of the linear equation 4x + 2y = 24 is y =-2x+12

Step-by-step explanation:

We need to write slope-intercept form of the linear equation 4x + 2y = 24

The standard equation of slope-intercept form is:

y=mx+b

Converting given equation in slope-intercept form.

4x + 2y = 24

Add -4x on both sides

2y = -4x+24

Divide both sides by 2

y =-2x+12

So, the slope-intercept form of the linear equation 4x + 2y = 24 is y =-2x+12

Keywords:  Slope-intercept form  

Learn more about Slope-intercept form at:

  • brainly.com/question/9369548
  • brainly.com/question/4932386
  • brainly.com/question/4819659

#learnwithBrainly

6 0
3 years ago
Due tomorrow plz help me
drek231 [11]
7y-3°=3y+13°
7y-3y= 13°+3°
4y= 16°
y=4°

Substitute y
7(4)-3°= 25°
3(4)+13=25°

180°-25°-25°=130°

2(2x+3)°+130°=180°
4x+136°=180°
4x=44°
x=11°
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How long would it take to travel 425 m at the rate of 50
Murljashka [212]
425 / 50 = 8,5

There you go.
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Can someone help me with this problem please thank youu how do you do it ?
icang [17]

Answer:

A) x = 6 y = 6√3

Step-by-step explanation:

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nadya68 [22]
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