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3 years ago

What is 278 minus 149

Mathematics

2 answers:

Basile [38]3 years ago

5 0

Answer:

129

Step-by-step explanation:

278 - 149 = 129

mr Goodwill [35]3 years ago

4 0

Answer:

the answer is 129

Step-by-step explanation:

278-149=129

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HELP ,<br> simplify a^3 a^10

Dominik [7]

A^13. Your welcome. :))

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3 years ago

Eduardo has purchased a home with an assessed value of $179,000. The property tax rate in his area is 2.3%. What is his monthly

ad-work [718]

Answer:

C. 343.08

Step-by-step explanation:

Convert the tax rate into a decimal and multiply by the house price:

.023(179,000) = 4,117

Divide by 12 (to get monthly rate):

4,117/12 ≈ 343.08

Option C should be the correct answer.

7 0

3 years ago

In a right triangle ABC angle B is the right angle and m angle C = 30 degrees if AC = 10 what is AB

Sindrei [870]

Answer:

AB = 5

Step-by-step explanation:

This is a 30°-60°-90° right triangle.

AC is hypotenuse, AB is opposite side to 30° angle.

We know that in such a triangle the side opposite to 30° angle is half the hypotenuse.

AB = 1/2AC = 1/2(10) = 5

8 0

3 years ago

A computer store buys a computer system at a cost of 474.60 $. The selling price was first at 791 , but then the store adverti

GalinKa [24]

So the question is the original price was $791 and they bought it at the marked down price at $474.60? then they saved $316.40 but i’m not really sure if that’s the question lol

5 0

3 years ago

Finding a polynomial of a given degree with given zeros

galben [10]

Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)

One of them is real and the other two are complex conjugate roots

Since the real root is 4, then

x = 4

Since the complex root is (1 - i), then

The other root will be the conjugate of it (1 + i)

x = (1 - i)

x = (1 + i)

To find f(x) we will multiply the three factors of it

We can get the factors from the zeroes

$x=4$

Subtract 4 from both sides

$\begin{gathered} x-4=4-4 \\ x-4=0 \end{gathered}$

The first factor is (x - 4)

$\begin{gathered} x=1-i \\ x-(1-i)=(1-i)-(1-i) \\ x-1+i=0 \end{gathered}$

The second factor is (x - 1 + i)

The third factor is (x - 1 - i)

$f(x)=(x-4)(x-1+i)(x-1-i)$

We will multiply them to find f(x)

$\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}$

Multiply it by (x - 4)

$\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}$

The answer is

$f(x)=x^3-6x^2+10x-8$

5 0

1 year ago