Question

Find g-1(x) when g(x)=3/5x-9

Answer 1

Answer:

$g^{-1}$(x) = $\frac{5x+45}{3}$

Step-by-step explanation:

let y = g(x) and rearrange making x the subject

y = $\frac{3}{5}$ x - 9 ( add 9 to both sides )

y + 9 = $\frac{3}{5}$ x

Multiply both sides by 5 to clear the fraction

5y + 45 = 3x ( divide both sides by 3 )

$\frac{5y+45}{3}$ = x

Change y back into terms of x, thus

$g^{-1}$(x) = $\frac{5x+45}{3}$