Solution :
2a + 2b = 7 ...1)
4a + 3b = 12 ...2)
In equation, 1)
a = (7 - 2b)/2 ...3)
Putting value of a in equation 2) we get :
4 × (7 - 2b)/2 + 3b = 12
2( 7 - 2b ) + 3b = 12
14 - 4b + 3b = 12
b = 2
Putting value of b in 3) we get :
a = ( 7 - 2×2)/2
a = 3/2 = 1.5
Now,
2x - 3y = 16 ...5)
x + 2y = -6 ...6)
x = -6 - 2y
Putting above value of x in eq 5) , we get :
2( -6 - 2y ) - 3y = 16
-12 - 4y - 3y = 16
7y = -28
y = -4
x = -6 - ( 2× -4 )
x = 2
Hence, this is the required solution.
Answer:
a) 
b) Lower endpoint: 0.422cc/m³
Upper endpoint: 0.452 cc/m³
Step-by-step explanation:
Population is approximately normal, so we can find the normal confidence interval.
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so
. This is the critical value, the answer for a).
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.
The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.
b)
Lower endpoint: 0.422cc/m³
Upper endpoint: 0.452 cc/m³
Answer: The wingspan is 36 m.
Using a proportion to solve this, we write the scale factor as a ratio first: 19/38, since 19 is the size of the model's length and 38 is the real length. For the second ratio, we have 18 for the size of the model wingspan and x for the real wingspan:
19/38 = 18/x
Cross multiply:
19*x = 38*18
19x = 684
Answer:
Step-by-step explanation:
the hypothenuse is the largest side in the right triangle
we have 2 side, 7,8
in a right triangle, c^2= a^2+b^2
where c is the hypothenuse
c^2=49+64=113
c=sqrt113=aprox 10.6
so, the answer is no if it has to be exactly 10 ft the hypotenuse
Answer:
(arranged from top to bottom)
System #3, where x=6
System #1, where x=4
System #7, where x=3
System #5, where x=2
System #2, where x=1
Step-by-step explanation:
System #1: x=4

To solve, start by isolating your first equation for y.

Now, plug this value of y into your second equation.

System #2: x=1

Isolate your second equation for y.

Plug this value of y into your first equation.

System #3: x=6

Isolate your first equation for y.

Plug this value of y into your second equation.

System #4: all real numbers (not included in your diagram)

Plug your value of y into your second equation.

<em>all real numbers are solutions</em>
System #5: x=2

Isolate your second equation for y.

Plug in your value of y to your first equation.

System #6: no solution (not included in your diagram)

Isolate your first equation for y.

Plug your value of y into your second equation.

<em>no solution</em>
System #7: x=3

Plug your value of y into your second equation.
