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kotegsom [21]
3 years ago
14

A software coder can type 79 words per minute. She works 5 eight hour days each week (not including

Mathematics
2 answers:
lions [1.4K]3 years ago
8 0

Answer:

A. 189,600

Step-by-step explanation:

(79×60)×5=23700

23700×8=189600

dexar [7]3 years ago
8 0

Answer: 189600

Step-by-step explanation:

If she can type 76 words per minute,

then to find the number of words she can type per hour, we simply multiply 79 by 60( because 1 hour = 60minutes)

79 × 60 =4740

Therefore she can type 4740words per hour

Now we proceed, she works 5 days in a week, and she works 8 hours per day

we need to get the total number of hours she works in a week, to get that, we simply multiply 8 by 5

8 × 5 = 40

which implies she works 40hours in a week

So, to get the total number of words she can type in a week,

we simply multiply 4740 × 40 = 189,600 words.

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Which of the following expressions has a value of 2/5 in the picture below?
Anuta_ua [19.1K]

Step-by-step explanation:

<u>Step 1:  List out all of the formulas for the trigonometric functions </u>

<em>sin(x) </em>= opposite/hypotenuse

<em>cos(x) </em>= adjacent/hypotenuse

<em>tan(x) </em>= opposite/adjacent

<u>Step 2:  Find the following expression that has a value of 2/5 </u>

sin(B) = opposite/hypotenuse = ?/5 is FALSE

cos(B) = adjacent/hypotenuse = 2/5 is TRUE

tan(B) = opposite/adjacent = ?/2 is FALSE

Answer:  The correction expression that has a value of 2/5 is option B

5 0
3 years ago
Explain or show how you could find by using the value of 5⋅3. If needed, use this diagram to support your reasoning.
Anika [276]

Answer:

Step-by-step explanation:

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8 0
3 years ago
What is my gpa if I have 4 A’s 1 B and 1 C
GenaCL600 [577]

Answer:

3.5

I,jJUiIJzuzusjdjusususuuss

8 0
3 years ago
Read 2 more answers
HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!
aksik [14]
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)








7 0
3 years ago
PLEASE HELP ME!!!!!!!!
juin [17]
That would be 242 divided by the total number of people surveyed, or 242/1028.

4 0
3 years ago
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