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noname [10]
2 years ago
15

Write a unit rate word problem. Please include the solution.

Mathematics
1 answer:
yanalaym [24]2 years ago
3 0

Answer:

bob goes 28 miles in 2 hours while traveling to the store. how many miles does he drive per hour. the answer is 14 miles per hour

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I need help with this is 8th grade math
Tresset [83]

Answer:

5 hours

Step-by-step explanation:

Mark recieves 3mg per hour. This can be rewritten as y=3x. Cassie recieves 2x+5. To solve, use substitiution. 3x=2x+5. To solve, subtract "2x" from "3x." You then get x=5.

5 0
2 years ago
Read 2 more answers
Find the value of x. 3) 2x (x + 21)​
Xelga [282]

To find the x-intercept, substitute in

0

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. To find the y-intercept, substitute in

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and solve for

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.

x-intercept(s):

(

0

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,

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−

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5 0
2 years ago
Geometry: The rectangle shown has a perimeter of 34cm and the given area. Its length is 5 more than twice it's width. Write and
Thepotemich [5.8K]

w - width

2w + 5 - length

w + w + (2w + 5) + (2w + 5) = 6w + 10 - perimeter

34 cm - perimeter

The equation:

6w + 10 = 34    <em>subtract 10 from both sides</em>

6w = 24    <em>divide both sides by 6</em>

w = 4 cm

2w + 5 = 2(4) + 5 = 8 + 5 = 13 cm

<h3>Answer: Width = 4cm, Length = 13cm</h3>
3 0
3 years ago
Someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi. We think the
denpristay [2]

Answer:

The sample size must be greater than 37 if we want to reject the null hypothesis.

Step-by-step explanation:

We are given that someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi.

Also, we are given a level of significance of 5%.

Let \mu = <u><em>mean breaking strength of their climbing rope</em></u>

SO, Null Hypothesis, H_0 : \mu = 2,000 psi       {means that the mean breaking strength of their climbing rope is 2,000 psi}

Alternate Hypothesis, H_A : \mu < 2,000 psi      {means that the mean breaking strength of their climbing rope is lower than 2,000 psi}

Now, the test statistics that we will use here is One-sample z-test statistics as we know about population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = ample mean strength = 1,997.2956 psi

            \sigma = population standard devaition = 10 psi

            n = sample size

Now, at the 5% level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

So, to reject our null hypothesis our test statistics must be less than -1.645 as only then we have sufficient evidence to reject our null hypothesis.

SO,  T.S. < -1.645   {then reject null hypothesis}

         \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < -1.645

         \frac{1,997.2956-2,000}{\frac{10}{\sqrt{n} } } < -1.645

         (\frac{1,997.2956-2,000}{10}) \times {\sqrt{n} } } < -1.645

          -0.27044 \times \sqrt{n}< -1.645

               \sqrt{n}> \frac{-1.645}{-0.27044}

                 \sqrt{n}>6.083

                  n > 36.99 ≈ 37.

SO, the sample size must be greater than 37 if we want to reject the null hypothesis.

7 0
3 years ago
Round 354,738 to the nearest thousand?
Alchen [17]
Your answer is 400,000.

Hope this helps!
7 0
3 years ago
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