How many different ways can 12 racecars finish in first, second, and third place?
1 answer:
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<h2>Hey!!</h2>
- <em>The distance between two trees is 5 meters.</em>
- <em>the distance between the first and last trees is 200 meters</em>
<em />
<em>To know the result of trees we will do the following steps...</em>
- <em>We will </em><em>divide the distance from the first to the last tree by 5</em><em>, and with this we would have the result:</em>
<h3>Result:</h3>
40 trees were planted
<h2><u><em>ATT- Brook2007s</em></u></h2>
The questions given in the pdf are these pictures, then we can get the solutions.
<u>1) Solution</u>
It is given that,
→ <5 = <6
Then the co interior angles,
→ <5+ <4 = 180°
Now substituting value of <5,
→ <6+ <4 = 180°
This shows property of co interior angle.
Therefore, L II m.
<u>2) Solution</u>
Take it as,
→ <1= 90°
In above eq. L is perpendicular to t.
→ <2 = 90°
In above eq. m is perpendicular to t.
Then it will be,
→ <1 = <2
It shows property of corresponding angle.
Therefore, L II m.
<u>3) Solution</u>
It is given that,
→ <1 = <2 and <1 = <3
Now substitute,
The value of <1 in second one,
→ <2 = <3
This shows property of alternate angle.
Therefore, ST II UV.
<u>4) Solution</u>
It is given that,
→ <RSP = <PQR --- (1)
→ <QRS + <PQR = 180° --- (2)
Now from the equation (1) and (2),
→ <RSP + <QRS = 180°
It shows property of co interior angle.
Therefore, PS II QR.
