Answer:
![y^2 + 8y + 16](https://tex.z-dn.net/?f=%20y%5E2%20%2B%208y%20%2B%2016%20)
Step-by-step explanation:
![(6y^2 + 2y + 5) - (5y^2 - 6y - 11) =](https://tex.z-dn.net/?f=%20%286y%5E2%20%2B%202y%20%2B%205%29%20-%20%285y%5E2%20-%206y%20-%2011%29%20%3D%20)
The first set of parentheses is unnecessary, so it can just be removed.
![= 6y^2 + 2y + 5 - (5y^2 - 6y - 11)](https://tex.z-dn.net/?f=%20%3D%206y%5E2%20%2B%202y%20%2B%205%20-%20%285y%5E2%20-%206y%20-%2011%29%20)
To remove the second set of parentheses, you must distribute the negative sign that is to its left. It changes every sign inside the parentheses.
![= 6y^2 + 2y + 5 - 5y^2 + 6y + 11](https://tex.z-dn.net/?f=%20%3D%206y%5E2%20%2B%202y%20%2B%205%20-%205y%5E2%20%2B%206y%20%2B%2011%20)
Now you combine like terms.
![= 6y^2 - 5y^2 + 2y + 6y + 5 + 11](https://tex.z-dn.net/?f=%20%3D%206y%5E2%20-%205y%5E2%20%2B%202y%20%2B%206y%20%2B%205%20%2B%2011%20)
![= y^2 + 8y + 16](https://tex.z-dn.net/?f=%20%3D%20y%5E2%20%2B%208y%20%2B%2016%20)
Answer:
1.02×10¹ = 10.2
Step-by-step explanation:
We have given a number in scientific notation as follows 1.02×10¹
We need to convert it into standard notation.
1 is in ones place, 0 is in tenths place and 2 is in hundredths place.
![1.02\times 10^1=\dfrac{102}{100}\times 10\\\\=\dfrac{102}{10}\\\\=10.2](https://tex.z-dn.net/?f=1.02%5Ctimes%2010%5E1%3D%5Cdfrac%7B102%7D%7B100%7D%5Ctimes%2010%5C%5C%5C%5C%3D%5Cdfrac%7B102%7D%7B10%7D%5C%5C%5C%5C%3D10.2)
So, the standard notation of 1.02×10¹ is 10.2
918x3=2754 the answer is 2757 wecome
I believe the person meant use pemdas! (order of opporations.)
you know what that is, right ? if you have questions feel free to message me!
Answer:
Dionne’s piece weight 500 grams heavier than Anthony’s
Step-by-step explanation: