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DIA [1.3K]
3 years ago
15

Does a graph compare two variables or not

Mathematics
1 answer:
Grace [21]3 years ago
5 0

Answer:

I believe it depends on the equations..

Step-by-step explanation:


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PLEASE HELP FAST I NEED 100% Contractor 3 gives Mrs. Solar the following fee table showing her charges for the contract work. a)
NARA [144]

rate of change is the slope

slope = (y2-y1)/(x2-x1)

m= (180-120)/(3-2)

m = 60/1

m = 60

b.  point slope form

y-y1 = m(x-x1)

y-120 = 60 (x-2)


c see attached graph.  x>=0 since it is hours

d the y intercept is

y -120 = 60x-120

add 120 to each side

y = 60x


3 0
3 years ago
Read 2 more answers
In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct a 95% conden
S_A_V [24]

Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that n = 42, \pi = \frac{26}{42} = 0.619

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 - 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.472

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 + 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.766

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

4 0
3 years ago
What I said the variable for 2a/3 = 3/4?<br><br><br> :: A=9/8 , A=6/8 or A= 1/2
JulijaS [17]
The answer is A. 9/8.
4 0
3 years ago
A shirt boutique purchased 100 new shirts for $1072. The short-sleeved shirts cost $10 each and the long-sleeved shirts cost $12
Scilla [17]

Answer:

one equation would be S+ L=36for the number of shirts sold.

4 0
3 years ago
Read 2 more answers
Three shipping companies want to compare the mean numbers of deliveries their drivers complete in a day.
Marianna [84]

Answer:

#1 is 10

# 2 is

6 + 7 + 8 + 9 + 10 + 10 + 10 + 12 + 14 + 14 = 100/10. The (Mean) = 10

(6- 10) + (7- 10) + (8- 10) + (9- 10) + (10- 10) + (10- 10) + (10- 10) + (12- 10) + (14- 10)

4 + 3 + 2 + 1 + 0 + 0 + 0 + 2 + 4

= 16/10 = 1 6/10

The (MAD) = 1 6/10

#3 Groups A & B

#4 sorry I can’t figure this out but I did 1/2/3

3 0
3 years ago
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