We are tasked to solve the value of p(8a) in the expression p(x)=3x^2-4.
This means that what would find the value of the expression when x=8a. To solve this, we simply substitute the value of x in the expression.
p(x)=3x^2-4
p(8a)=3(8a)^2-4
p(8a)=3(64a^2)-4
p(8a)=192a^2-4
Upper quartile would be 4.5. The interquartile range could be 6.
Answer
X= -0.5
Y=2
If you need me to explain I can.
Answer= 18
Explanation: you have to graph it on a grid paper first then make. Also trust me it’s the answer
assuming 10 numbers ( 0-9)
and 26 letters (A-Z)
10^4 x 26^2 = 6,760,000
