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3 years ago

9

Wednesday: Solve for x (can't use decimals), must use the rules.

1 answer:

Tanzania [10]3 years ago

8 0

Answer:

missing angle isosceles angle and side (a)

Pythagoras theorem

a²+a²=16²

a²=256/2

a=√128=11.3=11

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A youth chorus has 30 members. There are 14 boys in the chorus.

saw5 [17]

The ratio of boys to girls in simplest form is
14:16
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7/8
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What are the vertices of the hyperbola whose equation is (x+7)^2/25-(y-8)^2/32= 1?(−13, 8) and (−1, 8)

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Step-by-step explanation:

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4 years ago

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4 years ago

Adam works at a bakery. He uses 1/8 of his flour supply to make bread and 3/8 of his flour supply to make other baked goods. If

Olegator [25]

Answer:

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3 years ago

Someone plz help me with this asap!!!!!

Bas_tet [7]

Answer:

1.) $x=8\sqrt{3};y=16$

2.) $x=1;y=\frac{\sqrt{3}}{2}$

3.) $x=28 ; y=14\sqrt{3}$

4.) $x=24 ; y=12\sqrt{3}$

5.) $x=4\sqrt{3};y=8\sqrt{3}$

6.) $x=\frac{8\sqrt{3}}{3};y=\frac{16\sqrt{3}}{3}$

Step-by-step explanation:

Use the 30°-60°-90° formulas:

a. $longer$ $leg=\sqrt{3}*shorter$ $leg$

b. $hypotenuse=2*shorter$ $leg$

1.) Insert values for a:

$x=\sqrt{3}*8$

Simplify:

$x=8\sqrt{3}$

Insert values for b:

$y=2*8$

Simplify:

$y=16$

2.) Insert values for a:

$y=\sqrt{3}*\frac{1}{2}$

Simplify:

$y=\frac{\sqrt{3}}{2}$

Insert values for b:

$x=2*\frac{1}{2}$

Simplify:

$x=1$

3.) Insert values for a:

$y=\sqrt{3}*14$

Simplify:

$y=14\sqrt{3}$

Insert values for b:

$x=2*14$

Simplify:

$x=28$

4.)Insert values for a:

$y=\sqrt{3}*12$

Simplify:

$y=12\sqrt{3}$

Insert values for b:

$x=2*12$

Simplify:

$x=24$

5.) Insert values for a:

$12=\sqrt{3}*x$

Divide both sides by $\sqrt{3}$ and rationalize:

$\frac{12}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{12}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{12}{\sqrt{3}}\\\\\frac{12\sqrt{3}}{\sqrt{9}}\\\\\frac{12\sqrt{3}}{3}\\\\4\sqrt{3}=x$

Flip:

$x=4\sqrt{3}$

Insert values for b:

$y=2*4\sqrt{3}$

Simplify:

$y=8\sqrt{3}$

6.) Insert values for a:

$8=\sqrt{3}*x$

Divide both sides by $\sqrt{3}$ and rationalize:

$\frac{8}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{8}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{8}{\sqrt{3}}\\\\\frac{8\sqrt{3}}{\sqrt{9}}\\\\\frac{8\sqrt{3}}{3}=x$

Flip:

$x=\frac{8\sqrt{3}}{3}$

Insert values for b:

$y=2*\frac{8\sqrt{3}}{3}$

Simplify:

$y=\frac{16\sqrt{3}}{3}$

Finito.

5 0

3 years ago