Answer:
6. SAS Postulate
5. ASA Postulate
Step-by-step explanation:
The answer to your question would be C 6 can be put into 18 and 24
Given:
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
To find:
The equation of the perpendicular bisector of NY.
Solution:
Midpoint point of NY is




Slope of lines NY is




Product of slopes of two perpendicular lines is -1. So,


The perpendicular bisector of NY passes through (-4,1) with slope
. So, the equation of perpendicular bisector of NY is




Add 1 on both sides.

Therefore, the equation of perpendicular bisector of NY is
.
Answer:
Step-by-step explanation:
Subtract x on both sides

Divide both sides by 3

To find the y-intercept, let x = 0
y = 0, therefore the function crosses the y-axis at the origin.
To find the x-intercept, let y = 0
x = 0, therefore the function crosses the x-axis at the origin too.
The slope of the function is -1/3, from the origin, go down 1 and right 3
First start by subtracting:
50-8=42
the new equation is:
6x=42
then divide:
42/6=7
So the answer is:
x=7
Hope this helps!! :D