Look at the picture hopefully it helps at least a little.
I believe 2 7/15 is the answer:)
Answer:
<h2> 40in^3</h2>
Step-by-step explanation:
Step one:
given data
dimension of the box
lengh= 5 in
width= 2 in
height =4 in
Required
the volume of the box
the expression for the volume is
V=L*W*H
V=5*2*4
V=40 in^3
Hence the volume of sand the box can take is 40in^3
Think of the equation as the 10 times as parts so if Halle read ten times as more than Janet then we do the equation 264/11 because we have to include Janet's part too so Janet read 24, one part of the total while Halle read 240, 10 parts of the total
6t^-7 * 3t^5 = 1/6t^7 * 3t^5
