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aniked [119]
3 years ago
11

Before data is entered into the regression calculator, some data may be excluded. Explain why the data pair (0, 100) was exclude

d for the comparison of hours slept the night before and the test score. Describe what this data point represents. If it was included, would the trend line describe the data well?
I NEED A SAMPLE RESPONSE
Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:

2012

Step-by-step explanation:

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Solve each of the following systems by Gauss-Jordan elimination. (b) X1-2x2+ x3- 4x4=1 X1+3x2 + 7x3 + 2x4=2 -12x2-11x3- 16x4 5 (
Len [333]

Answer:

a) The set of solutions is \{(0,-3x_3,x_3): x_3\; \text{es un real}\} y b) the set of solutions is \{(-6,\frac{-41}{17}-\frac{30}{17}x_4 , \frac{37}{17}+\frac{8}{17} x_4 ,x_4): x_4\;\text{es un real}\}.

Step-by-step explanation:

a) Let's first find the echelon form of the matrix \left[\begin{array}{ccc}5&2&6\\-2&1&3\end{array}\right].

  • We add \frac{2}{5} from row 1 to row 2 and we obtain the matrix \left[\begin{array}{ccc}5&2&6\\0&\frac{9}{5} &\frac{27}{5}\end{array}\right]
  • From the previous matrix, we multiply row 1 by \frac{1}{5} and the row 2 by \frac{5}{9} and we obtain the matrix \left[\begin{array}{ccc}1&\frac{2}{5} &\frac{6}{5} \\0&1&3\end{array}\right]. This matrix is the echelon form of the initial matrix.

The system has a free variable (x3).

  • x2+3x3=0, then x2=-3x3
  • 0=x1+\frac{2}{5}x2+\frac{6}{5}x3=

       x1+\frac{2}{5}(-3x3)+\frac{6}{5}x3=

      x1-\frac{6}{5}x3+\frac{6}{5}x3

     then x1=0.

The system has infinite solutions of the form (x1,x2,x3)=(0,-3x3,x3), where x3 is a real number.

b) Let's first find the echelon form of the aumented matrix \left[\begin{array}{ccccc}1&-2&1&-4&1\\1&3&7&2&2\\0&-12&-11&-16&5\end{array}\right].

  • To row 2 we subtract row 1 and we obtain the matrix \left[\begin{array}{ccccc}1&-2&1&-4&1\\0&5&6&6&1\\0&-12&-11&-16&5\end{array}\right]
  • From the previous matrix, we add to row 3, \frac{12}{5} of row 2 and we obtain the matrix \left[\begin{array}{ccccc}1&-2&1&-4&1\\0&5&6&6&1\\0&0&\frac{17}{5}&\frac{-8}{5}&\frac{37}{5}   \end{array}\right].
  • From the previous matrix, we multiply row 2 by \frac{1}{5} and the row 3 by \frac{5}{17} and we obtain the matrix \left[\begin{array}{ccccc}1&-2&1&-4&1\\0&1&\frac{6}{5} &\frac{6}{5}&\frac{1}{5}\\0&0&1&\frac{-8}{17}&\frac{37}{17} \end{array}\right]. This matrix is the echelon form of the initial matrix.

The system has a free variable (x4).

  • x3-\frac{8}{17}x4=\frac{37}{17}, then x3=\frac{37}{17}+ \frac{8}{17}x4.x2+[tex]\frac{6}{5}x3+\frac{6}{5}x4=\frac{1}{5}, x2+\frac{6}{5}(\frac{37}{17}+\frac{8}{17}x4)+[tex]\frac{6}{5}x4=\frac{1}{5}, then

      x2=\frac{-41}{17}-\frac{30}{17}x4.

  • x1-2x2+x3-4x4=1, x1+\frac{82}{17}+\frac{60}{17}x4+\frac{37}{17}+\frac{8}{17}x4-4x4=1, then x1=1-\frac{119}{17}=-6

The system has infinite solutions of the form (x1,x2,x3,x4)=(-6,\frac{-41}{17}-\frac{30}{17}x4,\frac{37}{17}+ \frac{8}{17}x4,x4), where x4 is a real number.

6 0
3 years ago
Solve for W.<br><br> 4w-4+2(5w+8)=-2(w+3)<br><br> Simplify your answer as much as possible.
gayaneshka [121]

Answer:

w = -\frac{9}{8}

Step-by-step explanation:

The question is  4w-4+2(5w+8)=-2(w+3)

We can first use distributive property to simplify, the distributive property is  a(b+c)=ab+ac

Thus we have:

4w-4+2(5w+8)=-2(w+3)\\4w-4+10w+16=-2w-6

<em>Now we combine like terms and simplify to get the final answer for w</em><em>.</em>

4w-4+10w+16=-2w-6\\14w+12=-2w-6\\14w+2w=-6-12\\16w=-18\\w=\frac{-18}{16}\\w=-\frac{9}{8}

Thus, w = -\frac{9}{8}

8 0
3 years ago
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Jane threw a basketball up in the air. The following table represents the height f(t), in meters, of the ball above the ground a
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D. the ball touches the ground after 8 seconds
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Barry’s Bagel Emporium sells a dozen bagels for $5.00. This price is no longer high enough to create a profit. The owner decides
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Answer:

Plan C will be the fastest - it will take 10 weeks

Step-by-step explanation:

Plan A will take 60 weeks

Plan B will take the longest 104 weeks

Plan D will be the fastest - it will take 12 weeks

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1.3 to the second power
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