200$ because if you do 2000dovided by 10 then it will equal=200 so loook 200x10=2000 so 1/10=200
3m - 5p = 12
3m(-3m) -5p = (-3m)+ 12
-5p = -3m + 12
(-5)/-5p = (-5)/ (-3m + 12)
p = 3/5m + 12/-5
Answer:
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 9 - 1 = 8
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.8595
The margin of error is:
M = T*s = 1.8595*2.7 = 5
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams
The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
An equation of the form y = mx + b represents a linear function where m is the slope and b is the y-intercept. For example, y = 3x + 4 represents the linear function whose slope is 3 and whose y-intercept is 4.
Hope this helps!!! The reason why I asked which unit & lesson it is from, is because Idk if you go to k12 or not, by the pic, it looks like you do go to k12... IF you go to K12, I could tell you the answers, that's if I took that lesson... And that's if you'd tell me... Hope I make since.... Ok bye!!! :)