2 years ago

!!!ANSWER QUICKLY PLEASE!!! Please look at the screenshot below

Mathematics

1 answer:

olya-2409 [2.1K]2 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Four and two thirds add one and three fourths

Allushta [10]

Answer:

4 2/3 + 1 3/4 = 6 5/12

3 0

3 years ago

I really need help on question 19, 21, and 23 please help

ale4655 [162]

Answer:

there blurd out

Step-by-step explanation:

3 0

2 years ago

This year, a small business had a total revenue of $72,900. If this is 35% more than their total revenue the previous year, what

ziro4ka [17]

Answer:

Therefore there revenue was $540,000.

Step-by-step explanation:

Let their total revenue last year be x

35% of x = $72,9000 - x

or, 35/100 × x = 729000 - x

or, 7x/20 = 729000-x

or, 7x = 20(729000-x)

or, 7x = 1458000- 20x

or, 7x + 20x = 14580000

or, 27x = 14580000

or, x = 14580000/27

so, x = $540,000

4 0

3 years ago

Help me please I really need help

Ksju [112]

Answer:

Step-by-step explanation:

I'm having trouble explaining this one, sorry

5 0

2 years ago

Read 2 more answers

The edge length of a cube is changing at a rate of 10 in/sec. At what rate is the cube's volume changing when the edge length is

olya-2409 [2.1K]

Given:

The edge length of a cube is changing at a rate of 10 in/sec.

To find:

The rate by which cube's volume changing when the edge length is 3 inches.

Solution:

We have,

$\dfrac{da}{dt}=10\text{ in/sec}$

We know that, volume of cube is

$V=a^3$

Differentiate with respect to t.

$\dfrac{dV}{dt}=3a^2\dfrac{da}{dt}$

Substituting $\dfrac{da}{dt}=10$ and a=3, we get

$\dfrac{dV}{dt}_{a=3}=3(3)^2(10)$

$\dfrac{dV}{dt}_{a=3}=3(9)(10)$

$\dfrac{dV}{dt}_{a=3}=270$

Therefore, the volume increased by 270 cubic inches per sec.

7 0

2 years ago