Answer:
The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.
Step-by-step explanation:
The amount of water in the tank after 15 days is given by the series
910+(−710)+810+(−610)+⋯+310+(−110)+210
From the series, we can observe that, if water is added for a particular day then water will be drained the following day.
Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.
Hence, we can complete the series thus:
910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210
To evaluate this, we get
910-710+810-610+710-510+610-410+510-310+410-210+310-110+210
= 1610.0 gallons
Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.
Answer:
The required proof is shown below.
Step-by-step explanation:
Consider the provided figure.
It is given that KM=LN
We need to prove KL=MN
Now consider the provided statement.
KM = LN Given
KM = KL+LM Segment addition postulate
LN = LM+MN Segment addition postulate
KL+LM = LM+MN Substitution property of equality
KL = MN Subtraction property of equality
The required proof is shown above.
Answer:
42 13/20 km
Step-by-step explanation:
10 3/10+9 7/20+14 7/10+ 8 9/20=41+ (6+7+14+9)/20=41 + 1 13/20= 42 13/20 km
Answer:
Exact Form:
x = 1/64
Decimal Form:
x = 0.015625
Step-by-step explanation:
1. A)
7x= 3(35)
7x= 105
105/7= 15
Therefore x=15
2. C)
