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3 years ago

Please help me with this question

Mathematics

2 answers:

nasty-shy [4]3 years ago

7 0

Answer:

Graph C

Explanation:

If you were to plot a point anywhere on said graph. No point's y coordinate, would be the same. The can get infinitely closer together. But never have the same coordinate

PS:

Can I have Brainliest?

timurjin [86]3 years ago

3 0

I think the answer is c 90 percent chance

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How to find 36 is 22% of what number

Semmy [17]

Percent means parts out of 100 so
22%=22/100=0.22

'of' means multiply

'is' means =

36 is 22% of what
36=0.22 times what
divide both sides by 0.22
163.636363=what

the number is163.636363....

7 0

3 years ago

One of the parking lot lights at a hospital has a motion detector on it, and the equation (x+10)2+(y−8)2=16 describes the bounda

Pani-rosa [81]

We are given an equation:
$(x+10)^{2} + (y-8)^{2} = 16$

This is an equation of a circle. General form of a circle equation is:
$(x-a)^{2} + (y-b)^{2} = r^{2}$
Where:
a = x coordinate of a center
b = y coordinate of a center
r = radius of a circle

Motion detector can detect person anywhere within a boundary. The greatest distance at which detector can detect is at the edge of a circle. That distance, between detector and edge of circle, is equal to radius.

From the equation we have:
$r^{2} =16 \\ r=4$
The greatest distance at which person can be detected is 4ft.

7 0

3 years ago

Read 2 more answers

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago

Jeremiah is driving from Pensacola to Jacksonville. The graph shows his distance from Jacksonville. 36 E 320 28 240 20 160 120 4

3241004551 [841]

The speed is the change in position divided by the time.

There are four intervals where the speed is uniform:

1) from 0 to 0,5 hours
2) from 0,5 hours to 3 hours
3) from 3 to 4 hours
4) from 4 to 7 hours

We are asked to say the average speed during the interval in which J. is traveling the fastest.

That is where the is more inclined, and that happen in the last interval. There the speed is tha change in position / the time =
(200 -0)miles/3hours = 67 mph.

If you are not sure that this is the fastest speed, you can calculate the speed in the other intervals in the same way and compare.

8 0

4 years ago

I Will give out brainliest help ASAP

kirza4 [7]

Step-by-step explanation:

f(x) = 2x² + 9

f(5) = 2(5)² + 9

= 2(25) + 9

= 50 + 9

= 59

6 0

3 years ago

Please help me with this question​

Please help me with this question