Kropot72
kropot72 3 years ago
This can be solved by using a standard normal distribution table. The z-score for 34 pounds is 1, the reason being that 34 is one standard deviation above the mean of 28 pounds.
Can use the table to find the cumulative probability for z = 1.00 and post the result? If you do this we can do the next simple steps.
Answer:
x ≥ -1/2
Step-by-step explanation:
We know that we cannot graph imaginary numbers. Therefore, our <em>x </em>value has to be greater than or equal to 0:
To find our domain, we need to set the square root equal to zero:
√(4x + 2) = 0
4x + 2 = 0
4x = -2
x = -1/2
We now know that no value below -1/2 can be used or we will get an imaginary number. Therefore, our answer is x ≥ -1/2
Alternatively, we can graph the function and analyze domain:
Answer:
0.1587
Step-by-step explanation:
Here, mean=μ=100 and standard deviation=σ=16.
We have to find P(average MDI scores of 64 children > 102)=P(xbar>102).
n=64
μxbar=μ=100
σxbar=σ/√n=16/√64=16/8=2
P(xbar>102)=P((xbar-μxbar)/σxbar>(102-100)/2)
P(xbar>102)=P(z>1)
P(xbar>102)=P(0<z<∞)-P(0<z<1)
P(xbar>102)=0.5-0.3413
P(xbar>102)=0.1587
Thus, the probability that the average is greater than 102 is 15.87%
Answer:
0 = (3-2x) x (x x 2 -5)
(3-2x) x ( x x 2 - 5) = 0
(3-2x) x (2x - 5) = 0
3 - 2x = 0
2x - 5 = 0
x = 3/2
x = 5/2
x1 = 3/2 or x2 = 5/2
