(a) You can parameterize <em>C</em> by the vector function
<em>r</em><em>(t)</em> = (<em>x(t)</em>, <em>y(t)</em> ) = <em>P</em> (1 - <em>t </em>) + <em>Q</em> <em>t</em> = (2 - 2<em>t</em>, 7<em>t</em> )
where 0 ≤ <em>t</em> ≤ 1.
(b) From the above parameterization, we have
<em>r</em><em>'(t)</em> = (-2, 7) ==> ||<em>r</em><em>'(t)</em>|| = √((-2)² + 7²) = √53
Then
d<em>s</em> = √53 d<em>t</em>
and the line integral is

(c) The remaining integral is pretty simple,

That would be : 3:5 = 12:20....because 3/5 = 12/20
Answer:
We kindly invite you to see the image attached for further details.
Step-by-step explanation:
From Analytical Geometry we get that linear functions can be found after knowing a point and its slope. The standard form of a linear function is represented by the following formula:
(Eq. 1)
Where:
- Independent variable, dimensionless.
- Dependent variable, dimensionless.
- Slope, dimensionless.
- y-Intercept, dimensionless.
At first we need to calculate the y-Intercept, which is cleared within (Eq. 1):

If we know that
,
and
, then the y-Intercept of the linear function is:


Line with a slope of
that goes through the point (2, 1) is represented by
.
Lastly, we graph the line by using a plotting software (i.e. Desmos), whose result is included below as attachment.