The first term of the arithmetic progression exists at 10 and the common difference is 2.
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How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8
5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
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Answer:
volume
Step-by-step explanation:
At most she can listen to her music in 16 different ways.
Answer:
Claire traveled for 9 days.
Step-by-step explanation:
Given:
Total Distance traveled = 701 miles
Distance traveled each day = 80 miles
Distance traveled on last day = 61 miles
We need to find the number of days Claire traveled.
Solution:
Let the number of days Claire traveled be denoted by 'd'.
Now we can say that;
Total Distance traveled is equal to sum of Distance traveled each day multiplied by number of days and Distance traveled on last day.
framing in equation form we get;

Now Subtracting both side by 61 using Subtraction Property of Equality we get;

Now Dividing both side by 80 we get;

Hence Claire traveled 80 miles in 8 days and 61 miles on last day making of total <u>9 days</u> of travel.