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3 years ago

Use the Distributive Property and simplify the expression. 6+4(3x – 2)+5

1 answer:

8 0

First, we need to use the distributive property to simplify the expression. So, that means we have to multiply the 4 by all of the integers and variables inside the parentheses.

If done correctly, your expression should be 6+12x-8+5

Next, we should combine all of the constant terms (just numbers without variables), also known as combining like terms.

If done correctly, your expression should be 12x+3.

This matches answer B. 12x+3

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I need the answer for this question

Scrat [10]

Answer:

z=-13.9

Hope this helped!!

7 0

3 years ago

Read 2 more answers

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago

9decimals with 3 decimal places when rounded to the nearest hundredth round to 4.56.

suter [353]

? 123456.789 ?????

then round2(123456.789)

=123456.79

6 0

3 years ago

Read 2 more answers

Does anyone know the answer?

BaLLatris [955]

Answer: (11/2)π units.

Step-by-step explanation:

I've attached the solution.

Before seeing it there is a theorem you should remember.

The angle subtended by an arc of a circle at its center is twice of the angle it subtends anywhere on the circle’s circumference.

4 0

3 years ago

A mans weekly wage was £336 but now he earns £420. what is the percentage change

Arisa [49]

The percentage change from 339 to 420 is 21.34387%

6 0

3 years ago