I was never sure of what the "additive inverse" is.
So, just now, just for you, I went and looked it up.
The additive inverse of any number ' A ' is the number
that you need to ADD to A to get zero. That's all !
So now, let's check out the choices:
a), 6, -(-6)
That second number, -(-6), is the same as +6 .
So the two numbers are the same.
Do you get zero when you add them up ? No.
b). -7, 7
What do you get when you add -7 and 7 ?
You get zero.
So these ARE additive inverses.
c). -7, -7
What do you get when you add -7 to -7 ?
You get -14 . That's not zero, so these
are NOT additive inverses.
d). 7, 7
What do you get when you add 7 to 7 ?
You get 14. That's NOT zero, so these
are NOT additive inverses.
e). 6, -6
What do you get when you add 6 to -6 ?
You get zero.
So these ARE additive inverses.
What do we end up with from the list of choices:
a)., c)., and d). are NOT additive inverses.
b). and e). ARE additive inverses.
Answer: -5100
<u>Step-by-step explanation:</u>
![\sum^4_1[100(-4)^{n-1}]\qquad \rightarrow \qquad a_1=100\ \text{and r = -4}\\\\\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\\\\\S_4=\dfrac{100(1-(-4)^4)}{1-(-4)}\\\\\\.\quad=\dfrac{100(1-256)}{1+4}\\\\\\.\quad=\dfrac{100(-255)}{5}\\\\.\quad=20(-255)\\\\.\quad=-5100\\](https://tex.z-dn.net/?f=%5Csum%5E4_1%5B100%28-4%29%5E%7Bn-1%7D%5D%5Cqquad%20%5Crightarrow%20%5Cqquad%20a_1%3D100%5C%20%5Ctext%7Band%20r%20%3D%20-4%7D%5C%5C%5C%5C%5C%5CS_n%3D%5Cdfrac%7Ba_1%281-r%5En%29%7D%7B1-r%7D%5C%5C%5C%5C%5C%5C%5C%5CS_4%3D%5Cdfrac%7B100%281-%28-4%29%5E4%29%7D%7B1-%28-4%29%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B100%281-256%29%7D%7B1%2B4%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B100%28-255%29%7D%7B5%7D%5C%5C%5C%5C.%5Cquad%3D20%28-255%29%5C%5C%5C%5C.%5Cquad%3D-5100%5C%5C)
Answer:
Both are right.
Step-by-step explanation:
The two are both right.
Multiplication in algebra obeys the cummutative law ( a * b = b * a).
Answer:
6r+7=13+7r
6r+7=7r+13
6r+7−7r=7r+13−7r
−r+7=13
−r+7−7=13−7
−r=6
= 
r=−6
Step-by-step explanation:
:) This is the answer
Answer:a) L.C.M OF 2,3,5 is 30
THEREFORE=60/30+15/30÷10/30-6/30
=60/30+15/30×30/10-6/30(DMAS)
=60/30+3/2-6/30
=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.
=105/30-6/30
=105-6/30
=99/30
=33/10
b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3
