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ale4655 [162]
3 years ago
11

29/24 simplified help pls

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
6 0
1 5/24! brainliest please?
mote1985 [20]3 years ago
3 0
Decimal- 1.2083…
Mixed number- 1 5/24
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What is the value of x?
Lunna [17]

Answer:

x = 23 degrees

Step-by-step explanation:

sin theta = opposite side/ hypotenuse

sin x= 9/23

Take the arcsin of each side

arcsin( sinx) = arcsin (9/23)

x = arcsin (9/23)

x=23.03568411

Rounding to the nearest degree

x = 23 degrees

4 0
4 years ago
Helppppppppppppppppppppppppppppppppp
TiliK225 [7]
Answer:
The third choice is the correct one

Explanation:
Square root means that what is under the root has power of 1/2

8 = 4 * 2
Therefore:
√8 = √4 * √2 = 2√2

The given expression:
(8 * x^7 * y*8)^1/2 = (8)^1/2 * (x^7)^1/2 * (y^8)^1/2
                             = 2√2 * x^7/2 * y^4
                            = 2√2 * x^3 * y^4 * √x
                            = 2* x^3 * y^4 √2x

Hope this helps :)

6 0
4 years ago
Look at the table of values below. What is the missing term?<br><br> x 0 1 2 3 4 <br> y -2 -1 2 7 ?
Drupady [299]

The missing value in the table provided is 14.

4 0
3 years ago
Help please :(<br><br> What is the value of x?<br> Enter your answer in the box
harkovskaia [24]

Answer:

x = 65

Step-by-step explanation:

65 degress + 65 degrees + 50 degrees = 180 degrees

The triangle is supplementary. Hope this helps! :)

6 0
4 years ago
Read 2 more answers
Tess ran 4 3 3 4 ​ start fraction, 4, divided by, 3, end fraction kilometers each day for 2 22 days. Cam ran 2 3 3 2 ​ start fra
mestny [16]

We have been given that Tess ran \frac{4}{3} kilo-meters each day for 2 days.

Let us find total distance traveled by Tess in 2 days by multiplying \frac{4}{3} by 2 as:

\text{Distance traveled by Tess in 2 days }=\frac{4}{3}\times 2

\text{Distance traveled by Tess in 2 days }=\frac{4\times 2}{3}

\text{Distance traveled by Tess in 2 days }=\frac{8}{3}

We are also told that Cam ran  \frac{2}{3} kilo-meters each day for 5 days.

Let us find total distance traveled by Cam in 5 days by multiplying \frac{2}{3} by 5 as:

\text{Distance traveled by Cam in 5 days }=\frac{2}{3}\times 5

\text{Distance traveled by Cam in 5 days }=\frac{2\times 5}{3}

\text{Distance traveled by Cam in 5 days }=\frac{10}{3}

Since \frac{10}{3} km is greater than \frac{8}{3} km, therefore, Cam ran more kilo-meters in total and option B is the correct choice.

7 0
3 years ago
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