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V125BC [204]
2 years ago
14

Which statement about the figure MUST be true? Select all that apply.

Mathematics
1 answer:
olga55 [171]2 years ago
7 0
<h2>○=> <u>Correct options</u> :</h2><h2>□\color{plum}\tt\bold{(C) \: SR = 27}</h2><h2>□\color{plum}\tt\bold{(D) \: QR = 54 }</h2><h3><u>Steps to derive the correct options</u> :</h3>

Since two sides and one included angle is equal in △PQS and △PRS, we can conclude that they are congruent under the SAS congruence criterion.

Which means :

▪︎Angle S = Angle S

▪︎PS = PS

▪︎QS = RS

Given :

Measure of segment QS = 6n+3

Measure of segment RS = 4n+11

Thus :

= \tt6n + 3 = 4n + 11

= \tt6n + 3 - 4n = 11

=\tt 2n + 3 = 11

= \tt2n = 11 - 3

= \tt2n = 8

=\tt n =  \frac{8}{2}

\hookrightarrow\color{plum}\tt n = 4

Thus, the value of n = 4

Measure of segment QS :

=\tt 6n + 3

= \tt6 \times 4 + 3

= \tt24 + 3

\color{plum}\tt \: \bold{QS = 6n + 3 = \tt\bold{27}}

Thus, measure of QS = 27

Measure of RS :

=\tt 4n + 11

=\tt 4 × 4 + 11

=\tt 16+11

\color{plum}\tt \: \bold{RS = 4n + 11 = \tt\bold{27}}

Measure of QR :

=\tt 27+27

\color{plum}\tt \: \bold{QR = 27+27 \tt\bold{=54}}

Thus :

▪︎QS = 27

▪︎RS = 27

▪︎QR = 54

Therefore, the correct options are :

▪︎(C) SR = 27

▪︎(D) QR = 54

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Answer:

○ C

Explanation:

Accourding to one of the circle equations, \displaystyle (x - h)^2 + (y - k)^2 = r^2,the centre of the circle is represented by \displaystyle (h, k).Moreover, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must pay cloce attention to which term gets which symbol. Another thing you need to know is that the radius will ALWAYS be squared, so no matter how your equation comes about, make sure that the radius is squared. Now, in case you did not know how to define the radius, you can choose between either method:

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\displaystyle a^2 + b^2 = c^2 \\ \\ 6^2 + 8^2 = r^2 \hookrightarrow 36 + 64 = r^2 \hookrightarrow \sqrt{100} = \sqrt{r^2} \\ \\ \boxed{10 = r}

Sinse we are dealing with <em>length</em>, we only desire the NON-NEGATIVE root.

Distanse Equation

\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = d \\ \\ \sqrt{[-5 - 3]^2 + [3 + 3]^2} = r \hookrightarrow \sqrt{[-8]^2 + 6^2} = r \hookrightarrow \sqrt{64 + 36} = r; \sqrt{100} = r \\ \\ \boxed{10 = r}

Sinse we are dealing with <em>distanse</em>, we only desire the NON-NEGATIVE root.

I am joyous to assist you at any time.

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(n+3)(n-9)

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