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Simora [160]
3 years ago
9

Last year the girls’ basketball team had 8 fifth-grade students and 7 sixth-grade students. What was the ratio of sixth-grade st

udents to fifth-grade students on the team?
Mathematics
2 answers:
attashe74 [19]3 years ago
6 0

7:8 it could also be written as 7 to 8 or 7/8

Since we need to find out SIXTH to FIFTH grades we have to put the sixth graders first. Hope this helps and have a great day!

timofeeve [1]3 years ago
4 0

Answer:

the ratio of the sixth-grade students to fifth-grade students on the team is 7 : 8

Step-by-step explanation:

Given Parameters

Fifth grade students of the basket team = 8

Sixth grade students of the basket team = 7

Required;

Ratio of the sixth-grade students to fifth-grade students on the team

Let F represent the fifth graders

F = 8

Let S represent the sixth graders

S = 7

The ratio of S to F is represented mathematically by S : F

By substituton

S : F becomes

7 : 8

Hence, the ratio of the sixth-grade students to fifth-grade students on the team is 7 : 8

You might be interested in
Multiplicative inverse of fraction 4/12
docker41 [41]

Answer:

12/4

hope it helps!

Step-by-step explanation:

A multiplicative inverse is a reciprocal... A reciprocal is one of a pair of numbers that when multiplied with another number equals the number 1.

So the inverse of 4/12 is 12/4

Because 4/12*12/4= 1

5 0
3 years ago
Read 2 more answers
Total world consumption of iron was approximately 900 million tons in 1993. If consumption had increased by 2.5% each year and t
Lilit [14]

Step-by-step explanation:

We can model the annual consumption of iron by the equation

c = 900 million tons x 1.025^n, where

n is the number of years after 1993 and

c is the consumption for that year.

An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.

C = 900*10^6* \int\limits^n_0 {1.025^x} \, dx

This equation simplifies to

C = 900 million tons x (1.025^n - 1) / ln(1.025), where

x is a dummy variable and

C is the total consumption of iron n years after 1993.

Let R be the amount of iron remaining at n years after 1993, so

R = 480 billion tons - C

R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

We need to find the value of n when R is 0, so

0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

Simplify this equation to obtain

n = 107.4

So the iron will run out in the year 1993 + 107 = 2100

6 0
2 years ago
EVALUATE 8+3⋅4 OVER 2 THE ANSWERS ARE 8<br> 10<br> 16<br> 22
slavikrds [6]
PEMDAS so you do 3*4 which equals 12, then you add 8=20 20/2=10

7 0
3 years ago
If Upper X overbar equals 62​, Upper S equals 8​, and n equals 36​, and assuming that the population is normally​ distributed, c
marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=62 represent the sample mean

\mu population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size  

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=36-1=35

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0
3 years ago
The ratio of a to b is 9:2, and the ratio of c to b is 5:3. What is the ratio of a to c?
xz_007 [3.2K]
The answer is that the ratio of a to c is 9/5
8 0
3 years ago
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