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svetlana [45]
1 year ago
5

When we use a least-squares line to predict y values for x values beyond the range of x values found in the data, are we extrapo

lating or interpolating? are there any concerns about such predictions?.
Mathematics
1 answer:
BabaBlast [244]1 year ago
6 0

Option A is correct that is we are extrapolating. Because the pattern of the data may vary outside the x range, extrapolation is risky.

Given that,

We have to find are we extrapolating or interpolating when we use a least-squares line to forecast y values for x values outside the range of x values seen in the data.

Option A) We are extrapolating. Because the pattern of the data may vary outside the x range, extrapolation is risky.

<h3>What is extrapolation?</h3>

Extrapolation is the process of estimating, beyond the original observation range, the value of a variable on the basis of its relationship with another variable.

Therefore, Option A is correct that is we are extrapolating. Because the pattern of the data may vary outside the x range, extrapolation is risky.

To learn more about extrapolating visit: brainly.com/question/14643498

#SPJ4

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now find the measures of the angles by using 12.5 as x.

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angle CAD=6x
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check,
30+25+50+75=180°degrees

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Step-by-step explanation:

I know the measure of the triangle's third angle is 75 degrees because all the angles of a triangle add up to 180 degrees. So, I did 180-62-43 and got 75. So, in order for this triangle to be true, the third triangle would have to be 75 degrees.

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\boxed{The\:eighth\:number\:in\:the\:pattern\:is\:67.}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

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\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}

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