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otez555 [7]
3 years ago
14

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. Drawings not to scale T

he two figures above are congruent. Find the measure of the angle that isn't labeled on either figure. Please help me I have to get this done as fast as I can.
There is an shape with 86° and 41° and another shape with 133°.

Mathematics
1 answer:
Dima020 [189]3 years ago
3 0

Answer:

100°

Step-by-step explanation:

I assume the image is the one attached below.

The shapes are quadrilaterals, so their interior angles add up to 360°.  Three of those angles are 86°, 41°, and 133°.  So the fourth angle is:

x + 86° + 41° + 133° = 360°

x = 100°

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How many solutions are there to the equation below? 17 x - 8 = 3x + 16<br>maqth ​
vazorg [7]

Answer:

There is one solution and that answer is mixed number form  1 5/7 or exact form 12/7

Step-by-step explanation:

8 0
3 years ago
A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na
Oxana [17]

Answer:

(a) 2.29 km/h

(b) 9 km/h

Step-by-step explanation:

For part (a) you have to apply<em> the average speed formula</em>, which is defined by:

v=\frac{d}{t}

where d is the total distance traveled and t is the total time needed.

d=\frac{4.00}{1.75}=2.29 km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

The running time is:

T= 1.75 - 1.5 = 0.25 h

Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

t1+t2 = 0.25

You have to apply the formula d=vt before and after the nap:

-Before the nap, the distance traveled was 0.50 km

0.50 = v1t1

-Afer the nap, the distance traveled was 3.50 km

3.50=v2t2

But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

v1t1=0.50 (II)

2v1t2=3.50 (III)

Replacing (I) in (II)

v1(0.25-t2)=0.50

Applying distributive property and solving:

0.25v1-v1t2=.050

For (III) you have that v1t2=3.50/2=1.75. Hence:

0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

7 0
3 years ago
Given the foci of (8,0) and the difference of the focal radii = 6, find the equation of the hyperbola
k0ka [10]

Given :

The foci of hyperbola are (8,0) and (-8,0) .

The difference of the focal radii = 6.

To Find :

The equation of the hyperbola.

Solution :

We know, distance between foci is given by :

2c = 8 - (-8)

c = 8

Also, difference between the foci or focal distance is given by :

2a = 6

a = 3

Now, we know for hyperbola :

b^2 +a^2 = c^2\\\\b^2={c^2-a^2}\\\\b^2 = 64-9\\\\b^2 = 55

General equation of hyperbola is :

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\dfrac{x^2}{9}+ \dfrac{y^2}{55}=1

Hence, this is the required solution.

3 0
3 years ago
Pls i need help what is 1 plus 1?
aksik [14]

1+1 = 84, explanation is quite simple. i should get brainliiest

4 0
3 years ago
Erin made 66 devilled eggs for a party. After an hour, there were 8 left. How many eggs were eaten in the first hour?
kicyunya [14]

Hello There!

-What We Know-

Erin made 66 deviled eggs for a party.

After an hour 8 eggs were left.

X amount of eggs were eaten within the first hour.

——————————————————————————

We subtract 8 eggs how many were left after the hour

From how many eggs we had in total.

66-8=58.

58 eggs were eaten within the hour.

5 0
3 years ago
Read 2 more answers
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